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kompoz [17]
3 years ago
6

Although animals share many common characteristics, there is also a great amount of diversity found in animals. Which animals ar

e ectothermic, obtain dissolved oxygen in water through gills, have scales, have fins, and live in water? A) Fish B) Reptiles C) Mammals D) Amphibians
Biology
2 answers:
Stells [14]3 years ago
4 0
The answer you are looking for is A) Fish

Fishes are examples of Vertebrates. They are cold-blooded; obtain dissolved oxygen in water through gills; most of them lay eggs; have scales; have fins; live in water. 
olga55 [171]3 years ago
3 0

the answer is a. i did it on a quiz and got it right

You might be interested in
In a watershed system, the two main parts are the
torisob [31]
Found a similar question with the following choices:

a. living things and flowing water

b. climate and soil properties

c. physical setting and biological community

d. climate and landscape features

In a watershed system, the two main parts are the A. LIVING THINGS AND FLOWING WATER

8 0
3 years ago
Three linked autosomal loci were studied in smurfs.
cupoosta [38]

Answer:

height -------- color --------- mood

           (13.2cM)      (14.5cM)

C=0.421

I = 0.579

Explanation:

We have the number of descendants of each phenotype product of the tri-hybrid cross.

Phenotype Number

  • pink, tall, happy            580
  • blue, dwarf, gloomy     601
  • pink, tall, gloomy         113
  • blue, dwarf, happy      107
  • blue, tall, happy              8
  • pink, dwarf, gloomy        6
  • blue, tall, gloomy          98
  • pink, dwarf, happy      101

Total number of individuals = 1614 = N

Knowing that the genes are linked, we can calculate genetic distances between them. First, we need to know their order in the chromosome, and to do so, we need to compare the phenotypes of the parental with the ones of the double recombinants. We can recognize the parental in the descendants because their phenotypes are the most frequent, while the double recombinants are the less frequent. So:

Parental)

  • Pink, tall, happy            580 individuals
  • Blue, dwarf, gloomy      601 individuals

Simple recombinant)

  • Pink Tall Gloomy           113 individuals
  • Blue, Dwarf, Happy       107 individuals
  • Blue Tall Gloomy             98 individuals
  • Pink Dwarf Happy          101 individuals

Double Recombinant)  

  • Blue Tall Happy                 8 individuals
  • Pink  Dwarf Gloomy           6 individuals  

Comparing them we realize that parental and double recombinant individuals differ in the position of the gene codifying for <u>color</u><u>.</u> They only change in the position of Blue and Pink. This suggests that the position of the color gene is in the middle of the other two genes, height and mood, because in a double recombinant only the central gene changes position in the chromatid.  

So, the alphabetic order of the genes is:

---- height ---- color ----- mood ----

Now we will call Region I to the area between Height and Color, and Region II to the area between Color and Mood.

Once established the order of the genes we can calculate distances between them, and we will do it from the central gene to the genes on each side. First We will calculate the recombination frequencies, and we will do it by region. We will call P1 to the recombination frequency between Height and color genes, and P2 to the recombination frequency between color and mood.

P1 = (R + DR) / N

P2 = (R + DR)/ N

Where: R is the number of recombinants in each region (the ones that have an intermediate phenotypic frequency), DR is the number of double recombinants in each region, and N is the total number of individuals.  So:

Region I

Tall------ Pink--------happy  (Parental) 580 individuals

Dwarf ---Pink------- Happy (Simple Recombinant) 101 individuals

Dwarf--- Pink-------Gloomy (Double Recombinant) 6 individuals

Dwarf----Blue-------Gloomy (Parental) 601 individuals

Tall ------Blue------- Gloomy (Simple Recombinant)  98 individuals

Tall ----- Blue------- Happy   (Double Recombinant) 8 individuals  

Region II

Tall------ Pink--------happy (Parental) 580 individuals

Tall-------Pink------- Gloomy (Simple Recombinant) 113 individuals

Dwarf----Pink------- Gloomy (Double Recombinant) 6 individuals

Dwarf----Blue-------Gloomy (Parental) 601 individuals

Dwarf ----Blue-------Happy (Simple Recombinant) 107 individuals

Tall ----- Blue------- Happy   (Double Recombinant) 8 individuals

In each region, the highlighted traits are the ones that suffered recombination.

  • P1 = (R + DR) / N

P1 = (101+6+98+8)/1614

P1 = 213/1614

P1 = 0.132    

  • P2= = (R + DR) / N

P2 = (113+6+107+8)/1614

P1 = 234/1614

P1 = 0.145

Now, to calculate the recombination frequency between the two extreme genes, height and mood, we can just perform addition or a sum:

  • P1 + P2= Pt

0.132 + 0.145 = Pt

0.277=Pt

The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU). One centiMorgan (cM) equals one map unit (MU).  

The map unit is the distance between the pair of genes for which every 100 meiotic products, one results in a recombinant product.  

Now we must multiply each recombination frequency by 100 to get the genetic distance in map units:

GD1= P1 x 100 = 0.132 x 100 = 13.2 MU = 13.2 cM

GD2= P2 x 100 = 0.145 x 100 = 14.5 MU = 14.5 cM

GD3=Pt x 100 = 0.277 x 100 = 27.7 MU = 27.7 cM

To calculate the coefficient of coincidence, CC, we must use the next formula:

CC= observed double recombinant frequency/expected double recombinant frequency

Note:  

-observed double recombinant frequency=total number of observed double recombinant individuals/total number of individuals

-expected double recombinant frequency: recombination frequency in region I x recombination frequency in region II.

  • CC= ((6 + 8)/1614)/0.132x0.145

        CC=0.008/0.019

        CC=0.421

The coefficient of interference, I, is complementary with CC.

I = 1 - CC

I = 1 - 0.421

I = 0.579

8 0
3 years ago
Acetylcholine binds to a GPCR on heart muscle, making the heart beat more slowly. The activated receptor stimulates a G protein,
kogti [31]

Answer:

The correct answer is option (b) "addition of a drug that prevents the α subunit from exchanging GDP for GTP".

Explanation:

The G protein is a name given to a family of proteins that act as a switch in diverse cellular processes, transmitting signals from outside to inside of the cells. When a G protein receptor is activated by a neurotransmitter such as dopamine, the alpha subunit exchanges its GDP for a GTP and disassociates G-protein itself. An addition of a drug that prevents this action would prevent  G protein disassociation, which would enhance the effect of stimulating G protein that acetylcholine does.

6 0
3 years ago
Analysis of a blood sample from a fasting individual who had not eaten for 24 hours would be expected to reveal high levels of _
qaws [65]

Analysis of a blood sample from a fasting individuals who had not eaten for 24 hours be expected to reveal high levels of glucagon .

Hence the option B is correct .

<h3>What is glucagon ?</h3>

Glucagon is on of the natural hormone of the body .it is peptide hormone.

It is produced by alpha cells of the pancreas .

It controls bodily function which include it controls the glucose level in our body .

It will release in the response to drop in blood sugar due to prolonged fast ,exercise and protein rich meals .

Hence , OPTION B is correct .

Learn more about glucagon here :

brainly.com/question/14697323

#SPJ4

6 0
1 year ago
In anatomical position, the head is_______ to the cheat
den301095 [7]

superior


Think of superior as above, so since it is above it will be the end towards the head. Inferior is below so it will be closer to your feet since anatomical position is standing.

8 0
2 years ago
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