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Alja [10]
4 years ago
9

What are these signs for these expressions???

Mathematics
1 answer:
vekshin14 years ago
8 0

Answer:

look at the photo

Step-by-step explanation:

If you will need any help,don't hesitate to ask

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Step-by-step explanation:

Given that acceleration of an object is

\frac{dv}{dt} =-2v\\\frac{dv}{v} =-2dt\\ln v = -2t+C\\

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Since v(0) =7

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Hence lnv = -2t+ln 7\\v=7e^{-2t}

since velocity is rate of change of distance s we have

v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[

substitute t=0 and s=0

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So solution for distance is

s(t) =\frac{-7}{2} (e^{-2t}-1)

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