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svetoff [14.1K]
3 years ago
9

What’s the answer too this problem?

Mathematics
1 answer:
guapka [62]3 years ago
6 0

Think about the rule when multiplying powers together.

When multiplying two powers that have the

same base, simply add their exponents.

In this problem, each power has a base

of <em>a</em> and our exponents are <em>m </em>and <em>n</em>.

So adding these exponents together, we have a^m + n.

You might be interested in
Subtract the sum of 3y+7 and 5y-7 from4y-5
ivolga24 [154]
(3y + 7) + (5y-7)= 8y

(4y - 5)- 8y= -4y-5
4 0
3 years ago
A storage unit that has a square base has a volume of 480 ft3. The height of the unit is 7.5 feet. A prism has a length of l, wi
wolverine [178]

Answer: The area is 64

Step-by-step explanation:

It’s 64 because when you divide the volume 480ft by the height 7.5ft you get the area as 64ft.

8 0
3 years ago
Read 2 more answers
I need help plz and thanks
Ganezh [65]

For both of these questions, we have to use PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction. This is the order that we need to do things.

1.)

(1 x 2) x 3^2 x 4 + 5

Parentheses - multiplication

2 x 3^2 x 4 + 5

Exponents

2 x 9 x 4 + 5

Multiplication

72 + 5

Addition

<u>77</u>

2.)

8 + 6 x 3 x 4 x 8

Multiplication

8 + 576

Addition

<u>584</u>

6 0
4 years ago
An elevator has a placard stating that the maximum capacity is 1296 lb long dash — 8 passengers.​ So, 8 adult male passengers ca
Masja [62]

Answer:

There is a 98.26% probability that it is overloaded.

This elevator does not appear to be safe.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

Assume that weights of males are normally distributed with a mean of 170 lb, so \mu = 170

They have a standard deviation of standard deviation of 29 lb, so \sigma = 29.

We have a sample of 8 adults, so we have to find the standard deviation of the sample to use in the place of \sigma in the Z score formula.

s = \frac{\sigma}{8} = \frac{29}{8} = 3.625

Find the probability that it is overloaded because they have a mean weight greater than 162 lb, so X = 162

Z = \frac{X - \mu}{\sigma}

Z = \frac{162 - 170}{3.625}

Z = -2.21

Z = -2.21 has a pvalue 0.0174.

So, there is a 1-0.0174 = 0.9826 = 98.26% probability that it is overloaded.

Any probability that is above 95% is considerer unusually high. So, this elevator does not appear to be safe, since there is a 98.26% probability that it is overloaded.

8 0
3 years ago
A study was conducted to determine whether there were significant differences between medical students admitted through special
BabaBlast [244]

Answer:

A) 0.7696

B) 0.0474

C) Yes it's unusual

D) 0.05746

E) No, it is not unusual

F) No, it is not unusual

Step-by-step explanation:

This is a binomial probability distribution question.

We are told that 92.4% of those admitted graduated.

Thus; p = 92.4% = 0.924

From binomial probability distribution, q = 1 - p

Thus;

q = 1 - 0.924

q = 0.076

Formula for binomial probability distribution is;

P(x) = nCx × p^(x) × q^(n - x)

A) At least 11 graduated out of 12.

P(x ≥ 11) = P(11) + P(12)

P(11) = 12C11 × 0.924^(11) × 0.076^(12 - 11)

P(11) = 0.3823

P(12) = 12C12 × 0.924^(12) × 0.076^(12 - 12)

P(12) = 0.3873

P(x ≥ 11) = 0.3823 + 0.3873

P(x ≥ 11) = 0.7696

B) that exactly 9 of them graduated out of 12. This is;

P(9) = 12C9 × 0.924^(9) × 0.076^(12 - 9)

P(9) = 0.0474

C) We are not given significance level here but generally when not given we adopt a significance level of α = 0.05.

Now, exactly 9 out of 12 that graduated which is P(9) = 0.0474.

We see that 0.0474 is less than the significance level of 0.05. Thus, we can say that it is unusual to randomly select 12 students from the special programs and get exactly 9 that graduate

D) that at most 9 of them out of 12 graduated.

P(x ≤ 9) = P(0) + P(1) + P(2) + P(3) + P(4) + P(5) + P(6) + P(7) + P(8) + P(9)

This is going to be very long so I will make use of an online probability calculator to get the values of P(0) to P(8) since I already have P(9) as 0.0474.

Thus, we have;

P(0) = 0

P(1) = 0

P(2) = 0

P(3) = 0.00000001468

P(4) = 0.00000040161

P(5) = 0.00000781232

P(6) = 0.00011081163

P(7) = 0.00115477385

P(8) = 0.00877476184

Thus;

P(x ≤ 9) = 0 + 0 + 0 + 0.00000001468 + 0.00000040161 + 0.00000781232 + 0.00011081163 + 0.00115477385 + 0.00877476184 + 0.04741450256

P(x ≤ 9) = 0.05746

E) P(x ≤ 9) = 0.05746 is more than the significance level of 0.05, thus we will say it is not unusual.

F) from online binomial probability calculator, probability of getting only 9 out of 12 is more than the significance value of 0.05. Thus, we will say it is not unusual

7 0
3 years ago
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