1, -c/2 < -1.5 2. -y/2 < 6 3. -d/3 > -9
1 answer:
You might be interested in
Answer:
x=1/3
Step-by-step explanation:
A function f is given as
in the interval [0,1]
This function f being an algebraic polynomial is continuous in the interval [0,1] and also f is differntiable in the open interval (0,1)
Hence mean value theorem applies for f in the given interval
The value
Find derivative for f
Equate this to -5 to check mean value theorem
We find that 1/3 lies inside the interval (0,1)
Answer:
A function f(x) is said to be periodic, if there exists a positive real number T such that f(x+T) = f(x).
You can also just say: A periodic function is one that repeats itself in regular intervals.
Step-by-step explanation:
The smallest value of T is called the period of the function.
Note: If the value of T is independent of x then f(x) is periodic, and if T is dependent, then f(x) is non-periodic.
For example, here's the graph of sin x. [REFER TO PICTURE BELOW]
Sin x is a periodic function with period 2π because sin(x+2π)=sinx
Other examples of periodic functions are all trigonometric ratios, fractional x (Denoted by {x} which has period 1) and others.
In order to determine the period of the determined graph however, just know that the period of the sine curve is the length of one cycle of the curve. The natural period of the sine curve is 2π. So, a coefficient of b=1 is equivalent to a period of 2π. To get the period of the sine curve for any coefficient b, just divide 2π by the coefficient b to get the new period of the curve.
Hopefully this helped a bit.
