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garri49 [273]
3 years ago
8

Use the multiplication property of exponents to determine if each statement is true or false.

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
7 0
1)
LHS:
{a}^{4}  \times  {a}^{3}  \times a \\  =  {a}^{4 + 3 + 1}  \\  =  {a}^{7}
LHS = RHS. So, the statement is true

2)
LHS:
{5}^{2}  \times  {3}^{4}  \\  = 25 \times 81 \\  =  {5}^{2}  \times  {9}^{2}  \\  =   {45}^{2}
LHS not equal to RHS. So, the statement is false

3)
LHS:
{x}^{6}  \times  {x}^{0}  \times  {x}^{2}  \times  {x}^{3}  \\  =  {x}^{6 + 0 + 2 + 3}  \\  =  {x}^{11}
LHS = RHS. So, the statement is true.

4)
LHS:
7 {m}^{2}  \times 2m \times 4 {m}^{5}  \\  = (7 \times 2 \times 4) {m}^{2 + 1 + 5}  \\  = 56 {m}^{8}
LHS = RHS. So, the statement is true.
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the length of the shadow of a pole on level ground increases by 90m when the angle of elevation of the sun changes from 58 degre
Anarel [89]

Answer:

The height of the pole is 167 m

Step-by-step explanation:

The given parameters are;

Increase  in the length of the shadow = 90 m

Initial angle of elevation of the Sun = 58°

Final angle of elevation of the Sun = 36°

We have a triangle formed by the change in the length of the shadow and the rays from the two angle of elevation to the top of the pole giving an angle 22° opposite to the increase  in the length of the shadow  

We have by sin rule;

90/(sin (22°)  = (Initial ray from the top of the pole to the end of the shadow's length)/(sin(122°)

Let the initial ray from the top of the pole to the end of the shadow's length = l₁

90/(sin (22°)  = l₁/(sin(122°)

l₁ = 90/(sin (22°) ×(sin(122°) = 283.3 m

Therefore;

The height of the pole = 283.3 m × sin(36°) = 166.52 m

The height of the pole= 167 m to three significant figures.

3 0
3 years ago
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A right triangle is shown below.<br> Which measurement is the closest to the value of x?
REY [17]

Answer:

35°

Step-by-step explanation:

First you find the sine of x. That would be

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sinx = 57/100

sinx = 0.57

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Answer:

1.5 hours

Step-by-step explanation:

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distance = speed × time

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travelling at this rate then

time = \frac{distance}{speed} = \frac{93}{62} = 1.5 hours


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