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Ilia_Sergeevich [38]
3 years ago
10

Completely lost ! Need Help With This !

Mathematics
1 answer:
Anettt [7]3 years ago
8 0
80/5=16 cookies need 1 cup of flour
144/16= 9 cups to make 144 cookies
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Which equation could have been used to create this graph?
Galina-37 [17]
D

Remember starts at zero slope is up 4 right 1
Y= 4/1x+0
Y=4x
8 0
3 years ago
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I need help please please
kotegsom [21]

Answer:

k, a, and i  I think!

Step-by-step explanation:

5 0
3 years ago
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Does anyone know what the answer?
11111nata11111 [884]

Answer:

x = 7

Step-by-step explanation:

Hi,

7x - 7 = 4x + 14

3x - 7 = 14

3x = 21

x = 7

I hope this helps :)

5 0
3 years ago
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Convert 0.50 sen /g to RM/kg ​
IgorC [24]

the conversion is:

0.50 sen /g = 5 RM/kg

<h3>How to change the units?</h3>

First, we know that

1sen = 0.01RM

Then we can change:

0.50 sen /g = 0.50*(0.01 RM) /g = 0.005 RM/g

Now we use the relation:

1g = 0.001kg

So we can rewrite:

0.005 RM/g = 0.005 RM/(0.001kg) = 5 RM/kg

So the conversion is:

0.50 sen /g = 5 RM/kg

If you want to learn more about changes of units:

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7 0
2 years ago
A certain population of mice is growing exponentially. After one month there are 48. After 2 months there are "192" mice. Write
REY [17]

Answer:

P(t) = 12e^1.3863k

Step-by-step explanation:

The general exponential equation is represented as;

P(t) = P0e^kt

P(t) is the population of the mice after t years

k is the constant

P0 is the initial population of the mice

t is the time in months

If after one month there are 48 population, then;

P(1) = P0e^k(1)

48 = P0e^k ...... 1

Also if after 2 months there are "192" mice, then;

192 = P0e^2k.... 2

Divide equation 2 by 1;

192/48 = P0e^2k/P0e^k

4 = e^2k-k

4 = e^k

Apply ln to both sides

ln4 = lne^k

k = ln4

k = 1.3863

Substitute e^k into equation 1 to get P0

From 1, 48 = P0e^k

48 = 4P0

P0 = 48/4

P0 = 12

Get the required equation by substituting k = 1.3863 and P0 = 12 into equation 1, we have;

P(t) = 12e^1.3863k

This gives the equation representing the scenario

8 0
3 years ago
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