When
, we have


and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)
Suppose this is true for
, that

Now for
, we have

so we know the left side is at least divisible by
by our assumption.
It remains to show that

which is easily done with Fermat's little theorem. It says

where
is prime and
is any integer. Then for any positive integer
,

Furthermore,

which goes all the way down to

So, we find that

QED
Umm sorry i do not know that answer I am just getting the points for again so so so sorry ;(
The area of rectangle is 15x - 25y + 30 sqaure units
<em><u>Solution:</u></em>
Given that, a rectangle with a length of 5 and a width of 3x - 5y + 6
To find: Area of rectangle
<em><u>The area of rectangle is given by formula:</u></em>

From given,
Length = 5
Width = 3x - 5y + 6
<em><u>Substituting the values in formula, we get,</u></em>

Thus area of rectangle is 15x - 25y + 30 sqaure units
Answer:
11/9
hope this helped :)
Step-by-step explanation:
Answer:
Step-by-step explanation:
- Let the value of a number 'a' be = 8/15
- Let the value of a number 'b' be = 2/3
The difference between the two numbers can be calculated by subtracting the numbers












Thus,