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Zielflug [23.3K]
3 years ago
15

Explain how to solve 643 = 4x160 +n

Mathematics
2 answers:
BaLLatris [955]3 years ago
7 0
Omg really? Im in Middle School and i never saw anythin like this in Elementary School?????
Charra [1.4K]3 years ago
5 0
First you will have to multiply 4 and 160 which will be 640
then write 640 in the place of 4x160 so you should have 643=640+n
you then will subtract 640 with 640 and they should console out
then subtract 643 with 640 you should get 3 
so your answer should be 3=n
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Ayrıntılı bir şekilde çözümü yazarmısınız ​
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Step-by-step explanation:

4 0
2 years ago
Can someone please check my answer? thank you :)
Arisa [49]
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4 0
3 years ago
-3p-9=6<br> Solve equation for p then justify your reasoning
fredd [130]
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6 0
3 years ago
Read 2 more answers
Lisa sold $75 worth of play tickets.Adult tickets cost $4 each and children’s ticket cost $4 each.How many children’s tickets co
Helga [31]
Yes, there are many possible answers. An equation that can model your situation is:
4a+4b=75, with a being the amount of adult tickets sold, and b being the amount of children’s tickets sold.
Because both tickets cost 4 dollars, you would multiply the amount of tickets sold, by the price (in dollars) of the ticket.
So, you can find possible answers by substituting the amount of adult tickets sold. Say, 4 adults bought tickets. You could then substitute a for 4. So the equation would look like this.
4(4)+4b=75
16 + 4b = 75
4b = 75 - 16
4b = 59
Divide each side by four
B = 14.75

The reason you got a decimal number is because 75 cannot be divided by 4 evenly. So, in this context, you could say that 15 children bought tickets. One child had an issue, and Lisa gave them a 25% discount. This would explain why there are only 75 dollars worth in tickets. I hope I helped, this is my first question I have ever answered so I’m not entirely sure if this was helpful or not. Hope you figure this out!
3 0
3 years ago
What is the sum of the series?​
Mamont248 [21]

Answer:

45

Step-by-step explanation:

Since the values are relatively small substitute i = 1 to 5 into 3i and sum

(3 × 1) + (3 × 2) + (3 × 3) + (3 × 4) + (3 × 5)

= 3 + 6 + 9 + 12 + 15

= 45

6 0
3 years ago
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