Answer:
Use the formula,
Volume of cylinder =πr²h
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>3</em><em>.</em><em>1</em><em>4</em><em>×</em><em>1</em><em>6</em><em>×</em><em>1</em><em>1</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>5</em><em>5</em><em>2</em><em>.</em><em>6</em><em>4</em><em> </em><em>cm³</em>
Answer:
did that first one its false
A= 53, B= 100, C= 27 (the last option)
BC is the longest side because it is opposite the largest angle ( not true)
9514 1404 393
Answer:
(8.49; 225°)
Step-by-step explanation:
The angle is a 3rd-quadrant angle. The reference angle will be ...
arctan(-6/-6) = 45°
In the 3rd quadrant, the angle is 45° +180° = 225°.
The magnitude of the vector to the point is its distance from the origin:
√((-6)² +(-6)²) = √(6²·2) = 6√2 ≈ 8.4859 ≈ 8.49
The polar coordinates can be written as (8.49; 225°).
_____
<em>Additional comment</em>
My preferred form for the polar coordinates is 8.49∠225°. Most authors use some sort of notation with parentheses. If parentheses are used, I prefer a semicolon between the coordinate values so they don't get confused with an (x, y) ordered pair that uses a comma. You need to use the coordinate format that is consistent with your curriculum materials.
These are the answers. You subtract 6 from -3 giving you n≥-9. Since n/3 is a fraction, in order to undo it we must multiply it to the other side, giving us n≤-63.
1. n≥-9
3. n≤-63
I hope it helped!
