All categories

3 years ago

What is the domain and range?

Mathematics

2 answers:

guajiro [1.7K]3 years ago

6 0

Answer:

domain: your X values

range: your Y values

mariarad [96]3 years ago

6 0

Answer:

Domain = {-2, 1, 2}

Range = {-1, 2, 3}

Step-by-step explanation:

Domain is the set of x values required to find the resulting y values.

From the graph, whatever the function is,

when x = -2, y = 2

x = 1, y = -1

x = 2, y = 3

You might be interested in

5 times what equals .60

ahrayia [7]

Answer:

0.12

Step-by-step explanation:

8 0

3 years ago

The graph of the parent function f(x) = x is transformed such that g(x) = f(-2x). How does the graph of g(x) compare to the

Verdich [7]

Answer:

reflected across the y-axis
compressed by a factor of 2

Step-by-step explanation:

Replacing x by -x in f(x) causes it to be reversed horizontally, that is, reflected across the y-axis.

Replacing x by 2x in f(x) causes it to be compressed horizontally by a factor of 2.

Both of these transformations result in g(x) being a horizontally compressed horizontal reflection of f(x).

See the attachment for an example. The blue curve is g(x); the red curve is f(x).

3 0

4 years ago

Solve the word problem. Olivia has 21 coins in her drawer. Nine of the coins are nickels, and the rest are pennies. What is the

Maslowich

It will be 57 because if 9 are nickles in the rest are pennies

6 0

3 years ago

The number |x| is the distance between 0 and x. It can never equal a ____ number.

ololo11 [35]

Answer:

Negative number

Step-by-step explanation:

For example, |-5| = 55. This is because -5 is considered to be 5 units away from 0.

If this helps mark me brainliest please.

5 0

3 years ago

Read 2 more answers

Solve for x in the equation x2 + 14x+17--96

Veseljchak [2.6K]

Answer:

Option B.

Step-by-step explanation:

If a quadratic equation is defined as $ax^2+bx+c=0$ , the by quadratic formula

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Consider the given equation is

$x^2+14x+17=-96$

We need to find the value of x.

Add 96 on both sides.

$x^2+14x+17+96=-96+96$

$x^2+14x+113=0$

Here, a=1, b=14 and c=113. Using quadratic formula we get

$x=\dfrac{-14\pm \sqrt{14^2-4(1)(113)}}{2(1)}$

$x=\dfrac{-14\pm \sqrt{-256}}{2(1)}$

$x=\dfrac{-14\pm \sqrt{256}\sqrt{-1}}{2}$ $(\sqrt{-1}=i)$

$x=\dfrac{-14\pm 16i}{2}$

$x=-7\pm 8i$

The value of x are x=-7 + 8i and x=-7 - 8i.

Therefore, the correct option is B.

8 0

3 years ago