11 / 1/3
11 * 3/1
33/1
Fraction Form: 33/1
Simplified Form: 33
Answer:
your answers are already matched up
Step-by-step explanation:
Answer:
There is no sufficient evidence to support the executive claim
Step-by-step explanation:
From the question we are told that
The population proportion is 
The sample proportion is 
The sample size is 
The level of significance is 
The null hypothesis is 
The alternative hypothesis is 
Generally the test statistics is mathematically evaluated as

=> 
=> 
The p-value is mathematically represented as

Form the z-table

=> 
=> 
Given that
we fail to reject the null hypothesis
Hence we can conclude that there is no sufficient evidence to support the executive claim
Answer:
2
Step-by-step explanation:
We are given that Ticket writing on campus follows a Poisson process.
Last year the campus police wrote 1460 tickets
So, 
1 year = 365 days
So, E(Y) =
So, the standard deviation of the number of tickets written per day by the campus police = 
Hence the standard deviation of the number of tickets written per day by the campus police is 2
Answer:
I am thinking its 28 degree Fahrenheit