Answer:
65625/4(x^5)(y²)
Step-by-step explanation:
Using binomial expansion
Formula: (n k) (a^k)(b ^(n-k))
Where (n k) represents n combination of k (nCk)
From the question k = 5 (i.e. 5th term)
n = 7 (power of expression)
a = 5x
b = -y/2
....................
Solving nCk
n = 7
k = 5
nCk = 7C5
= 7!/(5!2!) ------ Expand Expression
=7 * 6 * 5! /(5! * 2*1)
= 7*6/2
= 21 ------
.........................
Solving (a^k) (b^(n-k))
a = 5x
b = -y/2
k = 5
n = 7
Substituting these values in the expression
(5x)^5 * (-y/2)^(7-5)
= (3125x^5) * (-y/2)²
= 3125x^5 * y²/4
= (3125x^5)(y²)/4
------------------------------------
Multiplying the two expression above
21 * (3125x^5)(y²)/4
= 65625/4(x^5)(y²)
2x + y = 1
3x - y = -6
---------------add
5x = -5
x = -5/5
x = -1
2(-1) + y = 1
-2 + y = 1
y = 1 + 2
y = 3
solution is (-1,3)
Answer:
x-6
Step-by-step explanation:
i believe this is correct.
I think it’s C because I did have this question but I’m not sure
Answer:
A. Converse
Step-by-step explanation:
The statement x=y and y=z is a
converse relation
In logic, there are different types of relation which includes
1. Inverse
2. Contrapositive inverse
3.converse
The converse is created by switching the hypothesis and conclusion just like the example given.
