Hello,
Please, see the detailed answer in the attached files.
Thanks.
I know it is probably to late for your answer but if you are on Solving and Reasoning with Complex Numbers: Tutorial in Edmentum, then the answer for part D on the first lesson activity is this word for word.
This equation generalizes the patterns seen in part D, where a and b represent real numbers:
(a + bi)(a − bi) = a2 + b2.
Hope this helps good luck
IF USING GEOMETRY...
x-axis = (x, -y)
Because the x does not have a negative sign the number DOES NOT change to its opposite form, but because the y has a negative sign the number DOES changes to its opposite form (from negative number to positive.)
So... if we use the formula of x-axis, which is (x, -y), the coordinates (-7,-3) would change to (-7, 3)
ANSWER (-7, 3)
The radicand of a quadratic is b^2-4ac.
If it is greater than zero, there are two real solutions
If it is equal to zero, there is one real solution
If it is less than zero, there are no real solutions (though there are two imaginary solutions)
In this case the discriminant is 256-2160 so it is less than zero.
Therefore there are no real solutions, though there are two imaginary solutions, specifically (16±i√-1904)/18
Answer:
Step-by-step explanation:
8(4y-20)
32(y-5)