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vlabodo [156]
2 years ago
14

Solve this please!!!!!!!!!!!!!!!!

Mathematics
1 answer:
coldgirl [10]2 years ago
4 0

Answer:

{y | y > 0}

Step-by-step explanation:

The range is the set of all values.

y cannot be zero, but it can be every value greater than zero.

The answer is at the bottom of the picture.

Answer: {y | y > 0}

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Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant
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The chain rule states that

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}

Since \ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2), you have

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and

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\dfrac{\mathrm dy}{\mathrm dt}=-\sin t
\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t

Also, since x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t, the derivative is

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Which choice is the solution?
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The solution for your answer is 12

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