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AlekseyPX
4 years ago
5

Val takes her four sons, Hal, Cal, Sal and Mal, to get their hair cut. It's crowded, so there's only time for two of them to get

a haircut. Val has to decide who goes first and who goes second. Below are her choices. Which ones are missing?
Mathematics
1 answer:
Elan Coil [88]4 years ago
3 0

Answer:

wait this doesn't mean :O (The dad took the kids)

Step-by-step explanation:

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PLEASE HELP ILL GIVE BRAINLIEST
Hatshy [7]

Answer:

Step-by-step explanation:

1. Find the function's zeros and vertical asymptotes, and plot them on a number line.

2. Choose test numbers to the left and right of each of these places, and find the value of the function at each test number.

3.Use test numbers to find where the function is positive and where it is negative.

4. Sketchh the function's graph, plotting additional points as guides as needed.

---

Give me brilliant please

8 0
3 years ago
(2^3 × 2)^2 pls explain how you got it....the answer is 2^8 but I want to know how we get that.
mario62 [17]

Step-by-step explanation:

(2³ × 2¹)²

(2⁶ × 2²)

for indices , × become +, plus

÷ become -, minus

so

2⁶+²

2⁸

6 0
3 years ago
How do i solve this step by step
AlladinOne [14]

Answer:

4) x^10

Step-by-step explanation:

1) If two numbers have the same base (i.e. x^3 and x^4) and you are multiplying them you just add the exponents. Therefore x^3*x^4 would be x^(3+4) which equals x^7.

2) When dividing similar bases you have to subtract the exponents. If we have x^18÷x^8 that is equivalent to x^(18-8) which gives us x^10.

3) If we have (x^3)^3 we will need to multiply the exponents. Therefore (x^3)^3 is equivalent to x^(3*3) which gives us x^9.

4) (x^2*x^4)^4÷x^8

First do what's in the parentheses,

(x^2*x^4) = x^6

Next do the exponents,

(x^6)^3 = x^18

Lastly the division,

x^18÷x^8 = x^10

x^10 is our answer.

4 0
4 years ago
Suppose you roll n ≥ 1 fair dice. Let X be the random variable for the sum of their values, and let Y be the random variable for
noname [10]

<u>Answer:</u>

X and Y are stochastically dependent RVs .

<u>Step-by-step explanation:</u>

Let ,

X = sum of the values that come up after throwing n (≥ 1) fare dice.

Y = number of times an odd number come up.

Let, n = 3

then, P(X =6) = p (say) clearly 0 < p < 1

and P (Y = 3) = \frac{1}{8}

And,

P( X = 6, Y = 3) = 0  ≠ P(X = 6) \times P(Y= 3)

Hence, X and Y are stochastically  dependent  RVs

3 0
3 years ago
Can someone help me please? <br><br> Thanks! <br><br> Please show your work and explain.
Liono4ka [1.6K]
1 Simplify 1/2x^2 to x^2/2
X^2/2 - x+5=0
2 Use the Quadratic Formula
x=1+3ı,1−3ı
So the answer is the first one a
6 0
3 years ago
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