1. Find the length of MK if JK=36, JL=48, and JN=60.

An arts academy required there to be 4 teachers for every 64 students and 6 tutors for every 48 students.How many students does

irina [24]

Answer:

1. 16 teachers 2. 8 tutor 3. 6 teachers

Step-by-step explanation:

3 0

3 years ago

Use always, sometimes or never to make a true statement:

viva [34]

Answer:

1. Intersecting lines are always coplanar

2. Two planes never intersect in exactly one point

3. Three points are always coplanar

4. A plane containing two points of a line always contains the entire line

5. Four points are sometimes coplanar

6. Two lines never meet in more than one point.

7. Two skew lines are never coplanar

8. Line TQ and Line QT are always the same line.

Step-by-step explanation:

Note: Coplanar means "In the same plane"

1. Each line exist in many planes. But different lines must share at least one plane for them to intersect. That is why intersecting lines are always coplanar.

2. Two planes never intersect at exactly one point because only lines intersect at a point. Planes can only intersect along a line.

3.Three points are always coplanar because in geometry, a group of points are coplanar because there is a geometric plane that they all lie on.

4. A plane containing two points of a line always contains the entire line. Yes

5. Four points are only sometimes coplanar because there is a probability that they may all not lie on the same plane

6. Two lines never meet in more than one point because lines are basically straight and cannot bend over to intersect at another point

7. Two skew lines are never coplanar because skews lines are lines that do not intersect and are never parallel.

8. Line TQ and Line QT are always the same line because a line is straight and extends from one point to the other. So, if a line is labelled TQ calling it QT means the same thing

4 0

2 years ago

Determine the unknown angle measures in the figure. HELP NOW!!! please

maw [93]

Answer:

m∠1=80°

m∠2=112°

m∠3=131°

m∠4=80°

m∠5=37°

Step-by-step explanation:

First you have to find m∠2

To do that find m∠6 (I created this angle shown in pic below)

Find m∠6 by using the sum of all ∠'s in a Δ theorem

m∠6=180°-(63°+49°)

m∠6=68°

Now you can find m∠2 with the supplementary ∠'s theorem

m∠2=180°-68°

m∠2=112°

Then you find m∠5 using the sum of all ∠'s in a Δ theorem

m∠5=180°-(112°+31°)

m∠5=37°

Now you can find m∠1

m∠1=180°-(63°+37°)

m∠1=180°-100°=80°

m∠4 can easily be found too now:

m∠4=180°-(63°+37°)

m∠4=80°

m∠3=180°-49°

m∠3=131°

8 0

3 years ago

20. Based on student records, 25% of the students at a large high school have a

Elenna [48]

Answer:

(E) 0.71

Step-by-step explanation:

Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.

So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:

P(A'∩B') = 1 - P(A∪B)

it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.

Therefore, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12

So, P(A∪B) is equal to:

P(A∪B) = P(A) + P(B) - P(A∩B)

P(A∪B) = 0.25 + 0.16 - 0.12

P(A∪B) = 0.29

Finally, P(A'∩B') is equal to:

P(A'∩B') = 1 - P(A∪B)

P(A'∩B') = 1 - 0.29

P(A'∩B') = 0.71

5 0

3 years ago

Read 2 more answers

What is the answer of -32/40 + -35/40 ?

Alex787 [66]

-32/40 + -35/40 = -32+-35/40
= -67/40
= -1.675

The answer would then be -1.675.

3 0

3 years ago