Answer:
Step-by-step explanation:
We can calculate this confidence interval using the population proportion calculation. To do this we must find p' and q'
Where p' = 14/100= 0.14 (no of left handed sample promotion)
q' = 1-p' = 1-0.14= 0.86
Since the requested confidence level is CL = 0.98, then α = 1 – CL = 1 – 0.98 = 0.02/2= 0.01, z (0.01) = 2.326
Using p' - z alpha √(p'q'/n) for the lower interval - 0.14-2.326√(0.14*0.86/100)
= -2.186√0.00325
= -2.186*0.057
= 12.46%
Using p' + z alpha √(p'q'/n)
0.14+2.326√(0.14*0.86/100)
= 0.466*0.057
= 26.5%
Thus we estimate with 98% confidence that between 12% and 27% of all Americans are left handed.
Answer:
1 1/2, 3 1/3
<h3>
Step-by-step explanation:</h3>
For the denominators (3, 4) the least common multiple (LCM) is 12. Calculations to rewrite the original inputs as equivalent fractions with the LCD:
10/3 = 10/3 × 4/4 = 40/12
6/4 = 6/4 × 3/3 = 18/12
<h3 /><h3 />
I believe the answer would be
f(x) = (x-3)^2 +5
