Answer:

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

And the net increase can be founded like this:
![Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642](https://tex.z-dn.net/?f=%20Test%20score_f%20-Tet%20score_i%20%3D%20557.8%20%2B36.7842%20Income-%20%5B557.8%20%2B36.42%20Income%5D%20%3D%2036.7842%20Income%20-36.42%20Income%20%3D%200.3642)
So then the net increase would be:
C. 0.36 points
Step-by-step explanation:
For this case we have the following linear relationship obtained from least squares between test scores and the student-teacher ratio:

If we increase the income by 1% that means that the new income would be 1.01 the before one and if we replace this we got:

And the net increase can be founded like this:
![Test score_f -Tet score_i = 557.8 +36.7842 Income- [557.8 +36.42 Income] = 36.7842 Income -36.42 Income = 0.3642](https://tex.z-dn.net/?f=%20Test%20score_f%20-Tet%20score_i%20%3D%20557.8%20%2B36.7842%20Income-%20%5B557.8%20%2B36.42%20Income%5D%20%3D%2036.7842%20Income%20-36.42%20Income%20%3D%200.3642)
So then the net increase would be:
C. 0.36 points
Average acceleration: ( v - v o ) / Δ t
v = 0 m/s, v o = 20 m/s, Δ t = 3.5 s
a (average) = ( 0 m/s - 20 m/s )/3.5 s = - 20 m/s / 3.5 s =
= - 5.7142857 m/s² ≈ - 5.71 m/s²
So I would round it to 340 and 40 because if the number is lower than 5 than take it DOWN to the nearest ten if it's five or above take UP to the nearest ten
Hope it helped you
Answer:
f =38
Step-by-step explanation:
f-3/4=5/6
f-3×6=5×4
f-18 =20
f =20+18
f =38