P(H,H,H)=P(H,T,H)
This is classical probability, so the probability of an event is the number of "favorable" events over total events.
The total number of events, by the counting principle, is 2^3=8.
The total number of events remains the same for P(H,H,H) and P(H,T,H), as you're still flipping 3 coins with two sides.
For P(H,H,H) the favorable event is (H,H,H) so 1, for P(H,T,H) the favorable event is (H,T,H) also one.
Conclusion:
P(H,H,H)=P(H,T,H)=1/8
Answer:
yea
Step-by-step explanation:
Answer:
a(5)=25
a2+a6=44
a(4)+2a(6)=93
sqrta(5)=5
Step-by-step explanation:
You are given all the terms needed but sometimes you will have to create a formula.
a(b)=6b-5 is the formula in this sequence, now you can just plug in everything.
a(5)=6(5)-5
=25
a2=7
a6=37
7+37=44
a(4)=19, a(6)=37
19+2(37)=93
a(5)=25
sqrt25=5
We notice that:
9-6 = 3
12-9 = 3 , Then we can conclude that this is an arithmetic progression with:
1st term a₁ = 6 and with common difference d = 3
So the first term is 6 and the last term is 93.
the formula of the sum in a A.P is :
S = (a + last term).n/2, n being the rank of the last term. So to be
able to find S, we have to calculate the value of n
We know that the last value of a A.P is :
last value = a₁ + (n-1)d
93 = 6 +(n-1)(3) → 93 = 6 + 3n -3 → n = 90/3 → n = 30 (rank 30th)
Now we can find the sum:
S = (a₁ + last term)n/2
S = (6+93)30/2
S = (99).15 = 1,485
Period: π; phase shift: x = π
