Find the area of the image below .

Mathematics

2 answers:

KATRIN_1 [288]3 years ago

8 0

<span>The answer is: A. 41 square units. Let point F be (6,5). The total area (A0) is the sum of the area (A1) of the right triangle A B F and the area (A2) of the square C D E F: A0 = A1 + A2. The area of the right triangle A B F is: A1 = (B F * A F)/2. From the image: B F = 10 units and A F = 5 units. So: A1 = (10 * 5)/2 = 50/2 = 25 square units. The area of the square is: A2 = C D * D E. From the image: C D = D E = E F = F C = 4 units. So: A2 = 4^2 = 16 units. From here, the total area is: A0 = A1 + A2 = 25 + 16 = 41 square units.</span>

Rudiy273 years ago

8 0

Answer:

its 41

Step-by-step explanation:

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The graph shows two lines, A and B.

scoundrel [369]

Answer:

second option: (4, 4) is the solution to both lines A and B.

Step-by-step explanation:

You know that the equation of line A is:

$y=-3x+15$

and the equation of line B is:

$y=\frac{1}{2}x+2$

The point in which the line A intersects with the line B is the solution of the sytstem of equations.

You can observe in given graph that the point of intersection of Line A and Line B is: (4,4)

Therefore (4, 4) is the solution to both lines A and B.

8 0

3 years ago

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A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant

Rasek [7]

Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

$\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10$