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3 years ago

6

Linear equations are a very important part of our world. Your job is to think of your own scenario for which a linear equation c

an be written. Describe your scenario and then write the linear equation in both slope-intercept and standard form.

1 answer:

larisa86 [58]3 years ago

6 0

When it means linear you have what inter acts with each standerd

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Help with this question, please!

uranmaximum [27]

Answer:

52 ft

Step-by-step explanation:

For each chord, the product of segment lengths is a constant. We can find that constant as the product of the segment lengths of the bisected chord:

(24 ft)·(24 ft) = 576 ft^2

Then the missing segment length (DX) of the diameter chord is ...

DX·(36 ft) = 576 ft^2

DX = (576 ft^2)/(36 ft) = 16 ft

So, the total length of the diameter chord is ...

DX +XL = 16 ft + 36 ft

DL = 52 ft

_____

We know DL is a diameter because the perpendicular bisector of any chord intersects the center of the circle.

5 0

3 years ago

Adding/subtracting polynomials <br>

Nuetrik [128]

Answer:

$g(x) - h(x) = { - x}^{4} - 11x$

Step-by-step explanation:

$g(x) = {6x}^{2} - 4x + {3x}^{4}$

$h(x) = {6x}^{2} + 4 {x}^{4} + 7x$

$g(x) - h(x)$

$({6x}^{2} - 4x + {3x}^{4}) - ( {6x}^{2} + 4 {x}^{4} + 7x)$

${6x}^{2} - 4x + {3x}^{4} - {6x}^{2} - 4 {x}^{4} - 7x$

$( {3x}^{4} - {4x}^{4}) + ( {6x}^{2} - 6x {}^{2} ) + ( - 4x - 7x)$

${ - x}^{4} - 11x$

6 0

3 years ago

Will give brainliest, please help fast

Gekata [30.6K]

Answer:

Converting the equation $x^2-20x+13=0$ into completing the square method we get: $\mathbf{(x-10)^2=87}$

Step-by-step explanation:

we are given quadratic equation: $x^2-20x+13=0$

And we need to convert it into completing the square method.

Completing the square method is of form: $a^2-2ab+b^2=(a-b)^2$

Looking at the given equation $x^2-20x+13=0$

We have a = x

then we have middle term 20x that can be written in form of 2ab So, we have a=x and b=? Multiplying 10 with 2 we get 20 so, we can say that b = 20

So, 20x in form of 2ab can be written as: 2(x)(10)

So, we need to add and subtract (10)^2 on both sides

$x^2-20x+13=0\\x^2-2(x)(10)+(10)^2-(10)^2+13=0\\(x^2-2(x)(10)+(10)^2) \:can\: be\: written\: as\: (x-10)^2 \\(x-10)^2-100+13=0\\(x-10)^2-87=0\\(x-10)^2=87$

So, converting the equation $x^2-20x+13=0$ into completing the square method we get: $\mathbf{(x-10)^2=87}$

4 0

3 years ago

Math math pls help pls

lord [1]

Answer:

30/5 than simplyply it to 6 0/5

3 0

2 years ago

In ΔABC, m∠CAB = 30°, M is the midpoint of

Thepotemich [5.8K]

Check the attached file for the answer.

3 0

3 years ago