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3 years ago

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Tom bought a computer for 15% off from the list price of p dollars. If the sales tax was 8%, how much did he pay for the compute

r including sales tax?

1 answer:

Dvinal [7]3 years ago

8 0

p-5 3\8%. 1111111111111111111111111

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PLEASE HURRY!!!

schepotkina [342]

9514 1404 393

Answer:

d. 76(cos(3π/16) +i·sin(3π/16))

Step-by-step explanation:

To form the product of 38cis(π/8) and 2cis(π/16), multiply the magnitudes and add the angles:

38cis(π/8) × 2cis(π/16) = (38×2)cis(π/8 +π/16) = 76cis(3π/16)

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In this context, a·cis(b) ≡ a(cos(b) +i·sin(b))

6 0

3 years ago

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Lizzie has already written 120 words of an essay. She writes 5 words per minute. Write an expression to represent the total numb

Wittaler [7]

Answer:

The Expression: 120 + 5m

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2 years ago

Write an equation of a line with the given slope and y-intercept. <br><br> m = –1, b = –6

loris [4]

Answer:

y = -x -6

Step-by-step explanation:

If we have a slope and a y intercept, we can use slope intercept form

y = mx +b , where m is the slope and b is the y intercept

y = -1x -6

y = -x -6

3 0

3 years ago

Read 2 more answers

Pls help me guys....???

tatuchka [14]

Answer:

1) 12/25

2) 1

3) 1/10

4) 1/4

5) 8/27

6) 9/20

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6 0

3 years ago

What is the solution of the system? Use elimination.

sweet [91]

Answer:

The solutions to the system of the equations by the elimination method will be:

$x=2,\:z=-1,\:y=2$

Step-by-step explanation:

Given the system of the equations

$2x\:+\:2y\:+z\:=\:7$

$-x-\:y\:+z\:=\:-5$

$x+3y-4z=12$

solving the system of the equations by the elimination method

$\begin{bmatrix}2x+2y+z=7\\ -x-y+z=-5\\ x+3y-4z=12\end{bmatrix}$

$\mathrm{Multiply\:}-x-y+z=-5\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-2x-2y+2z=-10$

$\begin{bmatrix}2x+2y+z=7\\ -2x-2y+2z=-10\\ x+3y-4z=12\end{bmatrix}$

$-2x-2y+2z=-10$

$+$

$\underline{2x+2y+z=7}$

$3z=-3$

$\begin{bmatrix}2x+2y+z=7\\ 3z=-3\\ x+3y-4z=12\end{bmatrix}$

$2x+6y-8z=24$

$-$

$\underline{2x+2y+z=7}$

$4y-9z=17$

$\begin{bmatrix}2x+2y+z=7\\ 3z=-3\\ 4y-9z=17\end{bmatrix}$

Rearranging the equations

$\begin{bmatrix}2x+2y+z=7\\ 4y-9z=17\\ 3z=-3\end{bmatrix}$

solve $3z=-3$ for z:

$z=-1$

$\mathrm{For\:}4y-9z=17\mathrm{\:plug\:in\:}z=-1$

solve $4y-9\left(-1\right)=17$ for y:

$4y-9\left(-1\right)=17$

$4y+9=17$

$4y=8$

$y=2$

$\mathrm{For\:}2x+2y+z=7\mathrm{\:plug\:in\:}z=-1,\:y=2$

solve $2x+2\cdot \:2-1=7$ for x:

$2x+2\cdot \:2-1=7$

$2x+3=7$

$2x=4$

$x=2$

Therefore, the solutions to the system of the equations by the elimination method will be:

$x=2,\:z=-1,\:y=2$

5 0

3 years ago