The numbers DO differ by 10 if they are
- 1 and 11
- 2 and 12
- 3 and 13
- 4 and 14
- 5 and 15
Each outcome technically has two ways of occurring, but since we're taking two marbles at a time, that would be the same as saying, for instance, that drawing 1 and 11 is the same as drawing 11 and 1. We only count such an event once.
So the answer is (a) 5.
4 cupcakes because if you do 12/ 1/.. you do kcf = to 12 x 1/3= 4
your welcome
<h3>
Answer: -16n-41</h3>
Work Shown:
2(-n-3) -7(5+2n)
2(-n)+2(-3) - 7(5)-7(2n) ... distribute
-2n - 6 - 35 - 14n
(-2n-14n) + (-6-35)
-16n - 41
Answer:
uhtvdbwiethweieigwhijgiwhgjwogw
Step-by-step explanation:
wdgqgsggdggd
9514 1404 393
Answer:
9. ±1, ±2, ±3, ±6
11. ±1, ±2, ±3, ±4, ±6, ±12
Step-by-step explanation:
The possible rational roots are (plus or minus) the divisors of the constant term, divided by the divisors of the leading coefficient.
Here, the leading coefficient is 1 in each case, so the possible rational roots are plus or minus a divisor of the constant term.
__
9. The constant is -6. Divisors of 6 are 1, 2, 3, 6. The possible rational roots are ...
±{1, 2, 3, 6}
__
11. The constant is 12. Divisors of 12 are 1, 2, 3, 4, 6, 12. The possible rational roots are ...
±{1, 2, 3, 4, 6, 12}
_____
A graphing calculator is useful for seeing if any of these values actually are roots of the equation. (The 4th-degree equation will have 2 complex roots.)