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Nitella [24]
3 years ago
8

53 - 21 + 62 + (25 ÷ 5)

Mathematics
1 answer:
Alisiya [41]3 years ago
4 0

Answer:

48

Step-by-step explanation:

So your equation is: 5y3 - 21 + 6y2 + (25 ÷ 5) and y = 2.

Evaluate for y=2

5(23)−21+6(22)+

25

5

5(23)−21+6(22)+

25

5

=48.

So the answer is 48.

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A car dealer just took delivery on forty new cars. He plans to put four of these cars on display at the front of the lot. In how
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B

Step-by-step explanation:

8 0
3 years ago
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In a plot of probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum
Lunna [17]

In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.

<h3>What is an electron?</h3>
  • The electron is a subatomic particle with a negative one elementary charge electric charge.
  • Electrons are the first generation of the lepton particle family and are widely regarded as elementary particles due to the lack of known components or substructure.

Electron in the hydrogen:

  • Hydrogen has the simplest electron configuration to write because it just contains one electron.
  • There is essentially only one electron surrounding the Hydrogen nucleus.
  • Because hydrogen only has one electron, its configuration is 1s1.
  • The maximum occurs at a0, the first Bohr radius, in a plot showing the chance of finding the electron in the hydrogen ground state vs the distance from the nucleus.

Therefore, in a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.

Know more about electrons here:

brainly.com/question/860094

#SPJ4

The complete question is given below:

In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs:

A. at a0. the first Bohr radius

B. at slightly less than a0

C. at slightly more than a0

D. at 2 a0

E. at a0/2

6 0
2 years ago
Explain how using equivalent ratios is like adding fractions with unlike denominators
Zielflug [23.3K]
It's kind of like division and mutliplycation I guess
7 0
3 years ago
2<img src="https://tex.z-dn.net/?f=%20%203%5E%28x%2B7%29%20%3D%20%209%5E%28x-1%29" id="TexFormula1" title=" 3^(x+7) = 9^(x-1)"
DaniilM [7]
3(x + 7) = 9(x - 1)
3(x) + 3(7) = 9(x) - 9(1)
  3x + 21 = 9x - 9
<u>- 3x          - 3x     </u>
          21 = 3x - 9
        <u>+ 9         + 9</u>
         <u>30</u> = <u>3x</u>
          3      3
         10 = x
4 0
3 years ago
PLEASE HELP IT’S DUE TMR
Soloha48 [4]
4 + 3 + 1 = 8

450000 divided by 8 = 56250

The first person gets 225000.

The second person gets 168750.

The last person gets 56250.

pls give me brainliest if it helped:)
4 0
3 years ago
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