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vazorg [7]
4 years ago
8

Two likes that do not intersect are parallel Always? Sometimes? Or Maybe?

Mathematics
1 answer:
earnstyle [38]4 years ago
3 0

Answer:

sometimes

Step-by-step explanation: They may not intersect at first but they may be put on a slight angle to where they may intersect in the longrun.

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<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cfrak%7B%20%5Corange%7B%20Question%7D%7D" id="TexFormula1" title=" \large\frak{ \
SVEN [57.7K]

Answer:

\boxed{\sf distance \: between \:  the \: objects \: \: is  \: 2.5 \: cm}

Step-by-step explanation:

According to universal law of gravitation every object in the universe attracts every other particles that surrounds it with a force which is inversely proportional to the square of their distance of separation & directly proportional to

the product of their masses, given by standard formula.

A = G \cdot  \frac{m_1.m_2}{ {d}^{2} }

where A,d & G are force of attraction, distance of separation & proportionality constant respectively.

<em>Given:</em>

A1 = 2 units

d1= 5 cm

A2 = 8 units

<em>To find:</em>

Distance of separation when the force of attraction is 8 units d2 = ?

<em>Solution:</em>

Substituting the given values in above at each point,

A_1 = G \cdot  \frac{m_1.m_2}{ {d_1}^{2} }  \\ 2 = G \cdot  \frac{m_1.m_2}{ {5}^{2} }  \\  \sf similarly  \: at \:  second \:  point \:  of  \: attraction \\  A_2 = G \cdot  \frac{m_1.m_2}{ {d_2}^{2} }  \\ 8 = G \cdot  \frac{m_1.m_2}{ {d_2}^{2} }  \\  \sf \: \: dividing \:  both  \: of \:  the \:  equation \\  \frac{2}{8}  =  \frac{G \cdot  \frac{m_1.m_2}{ {5}^{2} }}{G \cdot  \frac{m_1.m_2}{ {d_2}^{2} } }  \\  \sf \: G \: m_1 and \: m_2  \: are \:   \: constant  \: hence  \\ \sf  they \:  can  \: be  \: cancelled \:  out  \\  \frac{2}{8}  =  \frac{ \frac{1}{ {5}^{2} } }{ \frac{1}{ {d_2}^{2} } }  \\  \sf rearranging \: above \: equation \\  \frac{1}{4}  =  \frac{{d_2}^{2} }{ {5}^{2} }  \\ {d_2}^{2}  =   \frac{ {5}^{2} }{4 }  \\ {d_2}^{2}  =  \frac{25}{4}   \\ {d_2}^{2}  = 6.25 \\  \sqrt{{d_2}^{2} }  =  \sqrt{6.25}  \\  \boxed{ \sf{d_2} = 2.5 \: cm}

<em>Answer:</em><em> </em><em>the distance between the two </em><em>objects </em><em>is </em><em>2</em><em>.</em><em>5</em><em> </em><em>cm</em><em>, if the attraction between them is 8 </em><em>units.</em>

<em><u>Learn more about universal law of gravitation here brainly.com/question/27244479</u></em>

<em>Thanks </em><em>for </em><em>joining </em><em>brainly </em><em>community</em><em>!</em>

7 0
2 years ago
Find the slope and y-intercept of (x+2)(x+3)=(x-2)(x-3)+y​
allochka39001 [22]

Answer:

Slope: 10

y-intercept: (0,0)

5 0
4 years ago
Read 2 more answers
8) Which table shows a proportional relationship between x and y?
salantis [7]

Answer:

  D

Step-by-step explanation:

A table shows a proportional relationship if all of the y/x ratios are the same.

  A: 4/3 ≠ 10/6 . . . . not proportional

  B: 6/12 ≠ 12/14 . . . . not proportional

  C: 2/4 ≠ 20/20 . . . . not proportional

  D: 1/5 = 2/10 = ... = 5/25 . . . . proportional relationship

3 0
3 years ago
What is the difference of the fractions? Use the number line and equivalent fractions to help find the answer.
Thepotemich [5.8K]

To solve this question, we first need to layout the equation

-2 1/2 -(-1 3/4)

Step 1

-2 1/2-(-1 3/4) ... Equation

Step 2

5/2-(-1 3/4) ... Converted to improper fraction

Step 3

5/2-(-7/4) ... converted to improper fraction

Step 4

5/2--7/4 ... Got rid of parenthesis

Step 5

-3/4 ... Subtract

Answer:

-3/4 ... Answer

So the answer for this problem is C, -3/4

8 0
3 years ago
Read 2 more answers
Solve for k k/2 + 1/2 = 3
Sedaia [141]

k/2+1/2=3

Move +1/2 to the other side. Sign changes from +1/2 to -1/2

k/2+1/2-1/2=3-1/2

k/2=3-1/2

Find the common denominator for 3 and -1/2.

Common denominator is 2

k/2=3(2)-1/2

k/2= 6/2-1/2

k/2=5/2

Multiply k/2 with 2. Multiply 2 with 5/2

k/2 (2/1)=2(5/2)

Cross out 2 and 2. Divide by 2. Cross out 2 and 2 for 5/2(2). Divide by 2

k=5

7 0
4 years ago
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