Two likes that do not intersect are parallel Always? Sometimes? Or Maybe?

Mathematics

1 answer:

earnstyle [38]3 years ago

3 0

Answer:

sometimes

Step-by-step explanation: They may not intersect at first but they may be put on a slight angle to where they may intersect in the longrun.

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What is the sum or difference?

dlinn [17]

1. Ans: Option (B) $-6x^4$

Explanation:
Given: $2x^4 - 8x^4$
Take the common out:
=> $x^4(2 - 8)$

Hence: => $[tex]-6x^4$ [/tex] (Option B)

2. Ans: Option (D) $-3y^5$

Explanation:
Given: $6y^5 - 9y^5$
Take the common term(s) out:
=> $y^5(6-9)$

Hence: => $-3y^5$ (Option D)

3. Ans: Option (B) $9x^2 - 12x + 6$ quadratic trinomial

Explanation:
Given: $6 - 12x + 13x^2 - 4x^2$

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> $13x^2 - 4x^2 - 12x + 6$
=> $9x^2 - 12x + 6$ (Option B)

4. Ans: Option (C) $7.3x^2 + 0.8x + 1.3$

Explanation:
In order to find the total number of Common and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

Common guppies: $3.1x^2 +6.0x + 0.3$ 
Endler's guppies: $4.2x^2 - 5.2x + 1.0$
(add both)
-----------------------------------------------------------------
Total number: $7.3x^2 +0.8x + 1.3$
-----------------------------------------------------------------
Hence the ans is Option(C) $7.3x^2 + 0.8x + 1.3$

5. Ans: Option (D) $2x^2(133 - 18 \pi )$

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = $266x^2$

Now the area of the circular fountain:
Area of the Circular Fountain = $\pi r^2$
Since, r=6x
Therefore,
Area of the Circular Fountain = $\pi (6x)^2 = 36 \pi x^2$

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = $266x^2$ - $36 \pi x^2$
=> Final area of the Yard = $2x^2(133 - 18 \pi)$ (Option D)

6. Ans: Option (A) $56x^2$

Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = $60x^2$

Now the area of the stadium:
Area of the stadium = 1x * 4x = $4x^2$

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= $60x^2$ - $4x^2$
=> Final area of the lot = $56x^2$ (Option A)

-i

4 0

3 years ago

Read 2 more answers

ASAP ASAP ASAP SHOW WORK TOO !!!!!!!!!!!!!!! thanks soo much

k0ka [10]

A.
(64x² + 96x + 36) / (16x + 12)
= 4(16x² + 24x + 9) / 4(4x + 3)
= 4*(4x + 3)(4x + 3) / 4(4x + 3)
= 4x + 3

b.
1.79 x 10^5 = 1.79 * 100,000 = 179,000

c.
(5.9736 x 10^24) + (4.8685 x 10^24)
= (5.9736 + 4.8685) x 10^24
= 10.8421 x 10^24
= 1.08421 x 10^25

4 0

3 years ago

Kendrick walked 500 m per day, every day for one week. How many kilometers did he walk all together?

Ainat [17]

Answer:

3.5

Step-by-step explanation:

500 x 7

3500/1000

3.5

8 0

3 years ago