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2 years ago

Help me please help help help help

Mathematics

2 answers:

saw5 [17]2 years ago

4 0

Answer:

x=103

Step-by-step explanation:

Vertically opposite angles are equal to 180 so 180-77 = 103 giving you x.

sineoko [7]2 years ago

3 0

Answer:

Step-by-step explanation:

it is the same angle from one side and theother

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Using scientific notation, what is the solution to (2.82 * 104) * (3.1 * 103)?

MArishka [77]

Answer: Choice A) 8.742 * 10^7

=====================================

Work Shown:

$(a * 10^b) \times (c * 10^d) = a*c*10^{b+d}\\\\(2.82 * 10^4) \times (3.1 * 10^3) = 2.82*3.1*10^{4+3}\\\\(2.82 * 10^4) \times (3.1 * 10^3) = 8.742*10^{7}\\\\$

Extra info:

$8.742 * 10^7 = 87,420,000$

which is a little over 87.4 million

6 0

3 years ago

Is w = 8 a solution to the equation 5 + w = 58? Explain

sp2606 [1]

No.

Since w = 8, you must replace the variable with the number associated to it.

So, it would be 5 + 8 = 58

5 + 8 is not equal to 58, it is equal to 13.

If you wanted to find out what w was, simply subtract 5 on both sides.

w = 58 - 5

8 0

3 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is: