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melamori03 [73]
2 years ago
6

I would very appreciate help with this pretty soon.

Mathematics
2 answers:
BlackZzzverrR [31]2 years ago
4 0

Answer:

Step-by-step explanation: Hi there.

We can treat this problem just like a simple subtraction problem, like 3-2

It helps to form the equation like this:

x^2+9x+18

- (1x+06)

Remember that the operation changes the sign: -1x-6

The result is x^2+8x+12, and it is already in standard form.

Have a nice day! :)

Allushta [10]2 years ago
4 0

Answer:

x² + 8x + 12

Explanation:

given:

  • f(x) = x² + 9x + 18
  • g(x) = x + 6

solve function:

→ f(x) - g(x)

→ x² + 9x + 18 - (x + 6)

→ x² + 9x + 18 - x - 6

→ x² + 9x -x + 18 - 6

→ x² + 8x + 12

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PLEASE HELP I WILL MARK BRAINLIEST
mylen [45]

Answer:

8 x 13 = 104 yd^2

Step-by-step explanation:

To find the area of a rectangle we use the basic formula:

L x W

In this case 13 is your width and 8 is your length, multiply the two given lengths to get your area which is 104.

7 0
3 years ago
If y varies directly as x, and y is 18 when x is 5, which expression can be used to find the value of y when x is 11?
Leokris [45]

Answer: The value of y is 39.6 when x = 11 and the required expression is y(11) = 39.6

Step-by-step explanation:

Since we have given that

y varies directly as x.

If y = 18, when x = 5.

So, we need to find the value of y when x is 11.

According to question, we get that

\dfrac{y}{x}=\dfrac{18}{5}=\dfrac{y}{11}\\\\18\times 11=5y\\\\198=5y\\\\\dfrac{198}{5}=y\\\\y=39.6

Hence, the value of y is 39.6 when x = 11 and the required expression is y(11) = 39.6

5 0
3 years ago
Which equation has the solution x = 2?
romanna [79]

Answer:

3x + 2 = 8 \\ 3x = 6 \\ x =  \frac{6}{ 3}  \\ x = 2

3 0
3 years ago
HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME HELP ME
Kryger [21]

Answer:

1)

Given the triangle RST with Coordinates  R(2,1), S(2, -2) and T(-1 , -2).

A dilation is a transformation which produces an image that is the same shape as original one, but is different size.  

Since, the scale factor \frac{5}{3} is greater than 1, the image is enlargement or a stretch.  

Now, draw the dilation image of the triangle RST with center (2,-2) and scale factor \frac{5}{3}

Since, the center of dilation at S(2,-2) is not at the origin, so the point S and its image S{}' are same.

Now, the distances from the center of the dilation at point S to the other points R and T.  

The dilation image will be\frac{5}{3} of each of these distances,

SR=3, so S{}'R{}'=5 ;


ST=3, so S{}'T{}'=5  

Now, draw the image of RST i.e R'S'T'

Since, RT=3\sqrt{2} [By using hypotenuse of right angle triangle] and R{}'T{}'=5\sqrt{2}.


2)

(a)

Disagree with the given statement.

Side Angle Side postulate (SAS) states that:

If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle then these two triangles are congruent.

Given: B is the midpoint of \overline{AC} i.e \overline{AB}\cong \overline{BC}

In the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

Since, there is no included angle in these triangles.

∴ \Delta ABD is not congruent to \Delta CBD .

Therefore, these triangles does not follow the SAS congruence postulates.

(b)

SSS(SIDE-SIDE-SIDE) states that if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

Since it is also given that  \overline{AD}\cong \overline{CD}.

therefore, in the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{AD}\cong \overline{CD}   (SIDE)           [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

therefore by, SSS postulates \Delta ABD\cong \Delta CBD.

3)

Given that:  \angle1=\angle 3 are vertical angles, as they are formed by intersecting lines.

Therefore

, by the definition of linear pairs

\angle 1 and \angle 2 and \angle 3  and \angle 2 are linear pair.

By linear pair theorem, \angle 1 and \angle 2   are supplementary, \angle 2 and \angle 3  are supplementary.

m\angle1+m\angle 2=180^{\circ}

m\angle2+m\angle 3=180^{\circ}

Equate the above expressions:

m\angle 1+m\angle 2=m\angle 2+m\angle 3

Subtract the angle 2 from both sides in the above expressions

∴m\angle 1=m\angle 3

By Congruent Supplement theorem: If two angles are supplements of the same angle, then the two angles are congruent.


therefore, \angle 1\cong \angle 3.















3 0
2 years ago
Read 2 more answers
A circle has its center at the center of a square with 3-inch sides. Find the area of the square not covered by the circle Round
Aleonysh [2.5K]
So in order for us to know the area of the square that is not covered by the circle, we need to find first both the areas of the square and the circle.
So for the area of the square it is A = sxs. And for the circle is A = pi*r^2.
Let us find the area of the square first given that the side is 3 inches.
So A = 3*3
    A = 9 square inches.
Next is the area of the circle. Since the center of the circle is the same with the center of the square, the radius would be 1.5.
SO, A = (3.14)(1.5)^2
       A = 2.25 (3.14)
        A = 7.065 square inches.
Next, we deduct the area of circle from area of square and the result would be 1.935 <span>in². So the answer for this would be option B.
Hope this answer helps.</span>
7 0
3 years ago
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