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melamori03 [73]
3 years ago
6

I would very appreciate help with this pretty soon.

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
4 0

Answer:

Step-by-step explanation: Hi there.

We can treat this problem just like a simple subtraction problem, like 3-2

It helps to form the equation like this:

x^2+9x+18

- (1x+06)

Remember that the operation changes the sign: -1x-6

The result is x^2+8x+12, and it is already in standard form.

Have a nice day! :)

Allushta [10]3 years ago
4 0

Answer:

x² + 8x + 12

Explanation:

given:

  • f(x) = x² + 9x + 18
  • g(x) = x + 6

solve function:

→ f(x) - g(x)

→ x² + 9x + 18 - (x + 6)

→ x² + 9x + 18 - x - 6

→ x² + 9x -x + 18 - 6

→ x² + 8x + 12

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What is -4 3/8 - -1 1/4
Likurg_2 [28]

Answer:

Step-by-step explanation:

- 3 1/8

6 0
3 years ago
Nyla buys a birthday present for Nayelly. She finds a sweater that is originally $32 and a pair of socks that is $5.50. But the
LekaFEV [45]

Answer:

$22.50

Step-by-step explanation:

$32.00 *0.60=19.20

$5.50 * 0.60=3.30

19.20+3.30=$22.50

**I multiplied bu 0.60, because full price is 100% or 1.0,  but minus the 40% discount you are paying 60% or 0.60***

6 0
3 years ago
Read 2 more answers
PLEASE HELP THANKS!!!
MatroZZZ [7]

Answer:

235

Step-by-step explanation:

area of one square=

180

area of other square=

11 times 5 =55

55+180=235

please mark be as brainliest

5 0
3 years ago
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FREE BRAINLIST NEED HELP ASAP
Ede4ka [16]

Answer:

A)4.6 yard

Step-by-step explanation:

x^{2} +10^{2} =11^{2} \\x^{2} =21\\x=\sqrt[2]{21} \\

x≅4.6

Hoped I helped, have a nice day!

7 0
3 years ago
The faces of a cube are to be numbered with integers 1 through 6 in such a way that consecutive numbers are always on adjacent f
Blizzard [7]

Answer:

Total different ways to number the remaining faces is 10.

Step-by-step explanation:

It is given that consecutive numbers are always on adjacent faces (not opposite ones).

The face numbered 1 is on top and the face numbered 2 is toward the front.

Top = 1

Front = 2

The remaining faces are left right bottom back. Total possibilities are shown below.

S.no.      3                4              5               6

(1)       Right         Back         Bottom       Left  

(2)       Right         Back         Left         Bottom  

(3)       Right        Bottom       Left           Back  

(4)       Right        Bottom       Back         Left  

(5)       Bottom      Right         Back         Left  

(6)       Bottom       Left          Back        Right  

(7)       Left            Back       Bottom       Right  

(8)       Left            Back        Right         Bottom  

(9)       Left           Bottom      Right          Back  

(10)     Left            Bottom      Back         Right

When Bottom=3, then we can not place 4 on back because doing this 5 and 6 are opposite ones.

Therefore, total different ways to number the remaining faces is 10.

7 0
3 years ago
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