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Ugo [173]
2 years ago
8

Use the quadratic formula to solve. Round to the nearest tenth if necessary. 2x^2 -3x -7 = 0

Mathematics
1 answer:
abruzzese [7]2 years ago
8 0

The quadratic formula is:

\frac{-b + \sqrt{b^2 - 4ac} }{2a} and  \frac{-b - \sqrt{b^2 - 4ac} }{2a}

In this case, a = 2, b = -3, and c = -7

So, we can plug in the numbers to get:

  \frac{-(-3) + \sqrt{(-3)^2 - 4(2)(-7)} }{2(2)} and    \frac{-(-3) - \sqrt{(-3)^2 - 4(2)(-7)} }{2(2)}

Simplifying, we get:

    \frac{3 + \sqrt{65} }{4} and   \frac{3 - \sqrt{65} }{4}

You need to use a calculator to find what these would be in decimal form. The answer, rounded to the nearest tenth, is: x = 2.8, x = -1.3

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2) Use a graph to find the length of DE if D(4, -3) and E(-5, -7).​
noname [10]

Answer:

The answer rounded to the nearest tenth is 9.8.

Step-by-step explanation:

The answer itself is really long so I rounded to the tenths place.

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3 years ago
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Lady_Fox [76]
The answer is A. 35° Celcius
8 0
3 years ago
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$28 lunch; 15% tip what's the answer
Vlad [161]
To do this you want to first multiply 28 by 0.15.  This will give you $4.20.  You have to give a $4.20 tip.  The total cost would be the lunch and the tip added together.  It would give you a final total of $32.20.
4 0
3 years ago
Find the coordinates of the midpoint of the segment whose endpoints are H(10,1) and K(4,7)
zvonat [6]
Hey.
The answer is (7,4).
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6 0
3 years ago
HEY CAN ANYONE HELP ME!
nataly862011 [7]

Answer:

Given: In triangle ABC and triangle DBE where DE is parallel to AC.

In ΔABC and ΔDBE

DE || AC   [Given]

As we know, a line that cuts across two or more parallel lines.  In the given figure, the line AB is a transversal.

Line segment  AB is transversal that intersects two parallel lines.  [Conclusion from statement 1.]

Corresponding angles theorem: two parallel lines are cut by a transversal, then the  corresponding angles are congruent.

then;

\angle BDE \cong \angle BAC  and

\angle BEC \cong \angle BCA

Reflexive property of equality states that if angles in geometric figures can be congruent to themselves.

by Reflexive property of equality:

\angle B \cong \angle B  

By AAA (Angle Angle Angle) similarity postulates states that all three pairs of corresponding angles are the same then, the triangles are similar

therefore, by AAA similarity postulates theorem

\triangle ABC \sim \triangle DBE

Similar triangles are triangles with equal corresponding angles and proportionate side.

then, we have;

\frac{BD}{BA}                  [By definition of similar triangles]

therefore, the missing statement and the reasons are

Statement                                                                   Reason

3.\angle BDE \cong \angle BAC      Corresponding angles theorem

and  \angle BEC \cong \angle BCA        

5. \triangle ABC \sim \triangle DBE   AAA similarity postulates    

6. BD over BA                                                    Definition of similar triangle



7 0
2 years ago
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