$\text{We know}\ \sqrt{a}\ \text{is exist for}\ a\geq0.\\\\\text{Therefore the domain of}\ f(x)=3\sqrt{x-2}\ \text{is:}\\\\x-2\geq0\qquad\text{add 2 to both sides}\\\\\boxed{x\geq2\to x\in[2,\ \infty)}$

4 0

3 years ago

24.5×3.2 what is the answer

yanalaym [24]

Answer:

78.4

Step-by-step explanation:

count how many decimal places you have. solve the problem without the decimal places. add them back in the end.

4 0

3 years ago

Read 2 more answers

The length of a rectangle is 3 yd less than twice the width, and the area of the rectangle is 44 yd^2 Find the dimensions of the

vovangra [49]

Answer:

width: 5.5 yd; length: 8 yd

Step-by-step explanation:

Let w represent the width of the rectangle in yards. Then 2w-3 is the length and the area is the product of length and width:

w(2w-3) = 44

2w^2 -3w -44 = 0 . . . . put the equation into standard form

(w+4)(2w -11) = 0 . . . . . factor the equation

w = -4 or 11/2 . . . . . . . . the negative solution is extraneous

Then the length is 2·(11/2) -3 = 8.

The width of the rectangle is 5.5 yards; the length is 8 yards.

5 0

3 years ago