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astra-53 [7]
3 years ago
5

If a spider can move 1/2 of a mile every hour, then how many hours would it take for a

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Answer:

2

Step-by-step explanation:

   1/2x4=2

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What is the slope of a line perpendicular to the line whose equation is x-y=6x. Fully reduce your answer.
Over [174]

Answer  

1/5

Step-by-step explanation:

The slope of a perpendicular line is the negative reciprocal. Since y=-5x(m=-5), the slope is -(-1/5) which is 1/5

5 0
3 years ago
Read 2 more answers
Please help me I will give brainlist
Elena L [17]

Answer:

3 + 2n

Step-by-step explanation:

2 + 1 = 3.

2n cannot be added into this because it has a letter in front of it. Therefore, it stays on its own.

5 0
3 years ago
Read 2 more answers
Consider the two triangles.
GuDViN [60]

Answer:

(A)Show that the ratios StartFraction U V Over X Y EndFraction , StartFraction W U Over Z X EndFraction , and StartFraction W V Over Z Y EndFraction are equivalent.

\dfrac{UW}{XZ}=\dfrac{WV}{ZY}=\dfrac{UV}{XY}

Step-by-step explanation:

In Triangles WUV and XZY:

\angle VUW$ and \angle YXZ$ are congruent. \\\angle U W V$ and \angle X Z Y$ are congruent.\\ \angle U V W$ and \angle Z Y X$ are congruent.

Therefore:

\triangle UWV \cong  \triangle XZY

To show that the triangles are similar by the SSS similarity theorem, we have:

\dfrac{UW}{XZ}=\dfrac{WV}{ZY}=\dfrac{UV}{XY}

As a check:

\dfrac{UW}{XZ}=\dfrac{40}{32}=1.25\\\\\dfrac{WV}{ZY}=\dfrac{60}{48}=1.25\\\\\dfrac{UV}{XY}=\dfrac{50}{40}=1.25

The correct option is A.

4 0
3 years ago
A relative asked her aunt that lives in a certain part of the US to send her some money for food expenses in Canada. Her aunt se
scZoUnD [109]

Answer:

$6250

Step-by-step explanation:

if im correct plz can i get a brainliest

8 0
3 years ago
Y=750x+20,000 and y=950x+27,000 compare the two equations and summarize their differences
Lostsunrise [7]

Answer:

y = 200x + 7000

Step-by-step explanation:

950x-750x=200x

27,000-20,000=7000

hope this helps

6 0
2 years ago
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