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RoseWind [281]
3 years ago
11

A researcher posts a newspaper advertisement offering $20 in exchange for participation in a short study. The researcher accepts

the first five people who respond to the advertisement. Which of the following statements is true about the sample?
It is not a valid sample because it is only a short study.

It is a valid sample because money was offered to participants.

It is a valid sample because the first five people were selected to participate.

It is not a valid sample because it is not a random sample of the population.
Mathematics
2 answers:
Kamila [148]3 years ago
8 0

Answer:

It's D). It is not a valid sample because it is not a random sample of the population.

Step-by-step explanation:

I took the test and got it right.

Alona [7]3 years ago
3 0

Answer:

The answer is "It is not a valid sample because it is not a random sample of the population".

Step-by-step explanation:

I had this test and that was my answer, and it was correct.

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Write the computer program for;urgent​
AlladinOne [14]

ANSWER:

#include <stdio.h>

#define PAYRATE 10 //basic pay rate per hour

#define OVERTIME 15 //in excess of 40 hours a week

int NetPay(int hours);

int main()

{

int userWeeklyHours;

printf("Please enter your total weekly working hours: \n");

scanf("%d", &userWeeklyHours);// get the user weekly hours

NetPay(userWeeklyHours);

return 0;

}

int NetPay(int hours)// implementing the function to calculate total pay, total taxes, and net pay

{

int firstRate, secondRate, restOfRate, secondAmount, rest, payAfterTax, payedBeforeTax, overHours;

if (hours > 40)

{

overHours = hours - 40;

payedBeforeTax = (40 * PAYRATE) + (overHours * OVERTIME);

}

else

payedBeforeTax = hours * PAYRATE;//defining the user first paycheck before taxes

if (payedBeforeTax <= 300)//paying only first rate case

{

firstRate = payedBeforeTax*0.15;

payAfterTax =payedBeforeTax - firstRate;

printf("your total gross is %d, your taxes to pay are %d, your net pay is %d", payedBeforeTax, firstRate, payAfterTax);

}

else if (payedBeforeTax > 300 && payedBeforeTax <= 450)//paying first and second rate

{

secondAmount = payedBeforeTax - 300;

firstRate = (payedBeforeTax - secondAmount) * 0.15;

secondRate = secondAmount * 0.20;

payAfterTax = payedBeforeTax - (firstRate + secondRate);

printf("your total gross is %d, your taxes to pay are %d, your net pay is %d", payedBeforeTax, firstRate + secondRate, payAfterTax);

}

else if (payedBeforeTax > 450)// paying all rates

{

rest = payedBeforeTax - 450;

secondAmount = (payedBeforeTax - 300) - rest;

firstRate = (payedBeforeTax - (rest + secondAmount)) * 0.15;

secondRate = secondAmount * 0.20;

restOfRate = rest * 0.25;

payAfterTax = payedBeforeTax - (firstRate + secondRate + restOfRate);

printf("your total gross is %d, your taxes to pay are %d, your net pay is %d", payedBeforeTax, firstRate + secondRate + restOfRate, payAfterTax);

}

return payAfterTax;

}

8 0
3 years ago
Find 5 rational numbers between 3/5 and2/3​
Novay_Z [31]

Answer:

The 5 rational are 91/150 , 92/150 , 93/150 , 94/150 , 95/150

Step-by-step explanation:

We have to fine 5 rational numbers between

3/5 and 2/3

First we have to make the denominator same

3/5= 3/5 ×3/3 = 9/15 =9/15×10/10 =90/150

2/3 = 2/3×5/5 = 10/15 = 10/15×10/10 = 100/150

The 5 rational numbers are

91/150 , 92/150 , 93/150 , 94/150 , 95/150

hope this helps :)

3 0
3 years ago
Find the shaded sector and the length of the arc. Round to the nearest hundredth. ​
Dovator [93]

Answer:

Step-by-step explanation:

I'll show you how to do the first one; the other are exactly the same, so pay attention.

The formula for arc length is

AL=\frac{\theta}{360}*2\pi r where θ is the central angle's measure. It just so happens that the measure of the central angle is the same as the measure of the arc it intercepts. Our arc shows a measure of 40°; this measure is NOT the same as the length. Measures are in degrees while length is in inches, or cm, or meters, etc. Going off that info, our central angle measures 40°. Filling in the formula and using 3.1415 for π:

AL=\frac{40}{360}*2(3.1415)(3). I'm going to reduce that fraction a bit (and I'll use the same reduction in the Area of a sector coming up next):

AL=\frac{1}{9}*2(3.1415)(3) which makes

AL = 2.09 units. Now for Area of the Sector. The formula is almost identical, but instead uses the idea that the area of a circle is πr²:

A_s=\frac{\theta}{360}*\pi r^2 where θ is, again, the measure of the central angle (which is the same as the measure of the arc it intercepts). Filling in:

A_s=\frac{1}{9}*(3.1415)(3)^2 which simplifies a bit to

A_s=\frac{1}{9}*(3.1415)(9). As you can see, the 9's cancel each other out, leaving you with

A_s=3.14 units²

7 0
2 years ago
Read 2 more answers
Given the following data set 2,3,1,6,1,1,1,0,2,4,5,1,2,2,3<br>Mean <br>Median <br>Range<br>Mid range
igomit [66]

Answer:

mean: 34/15=2.27

median: 2

range: highest-lowest...... 6-0=6

mid range: high + low divided by 2

6+0=6/2=3

8 0
3 years ago
Read 2 more answers
Can someone help me with this please
STALIN [3.7K]
You can’t evaluate that I’m pretty sure
8 0
2 years ago
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