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julia-pushkina [17]
3 years ago
10

WHO WANTS FREE BRAINLY AND TEN POINTS???

Mathematics
2 answers:
ycow [4]3 years ago
5 0

Answer:

hi i like cheese

Step-by-step explanation:

wolverine [178]3 years ago
4 0

Answer:

meeeeeee

Step-by-step explanation:

PLEASE

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If sin theta = (4)/(7)​, theta in quadrant​ II, find the exact value of (a) cos theta (b) sin (theta + (pi) / (6) ) (c) cos (the
EleoNora [17]

Answer:

a) \cos(\theta) = \frac{\sqrt[]{33}}{7}

b) \sin(\theta + \frac{\pi}{6})\frac{-3\sqrt[]{11}+4}{14}

c) \cos(\theta-\pi)=\frac{\sqrt[]{33}}{7}

d)\tan(\theta + \frac{\pi}{4}) = \frac{\frac{-4}{\sqrt[]{33}}+1}{1+\frac{4}{\sqrt[]{33}}}

Step-by-step explanation:

We will use the following trigonometric identities

\sin(\alpha+\beta) = \sin(\alpha)\cos(\beta)+\cos(\alpha)\sin(\beta)

\cos(\alpha+\beta) = \cos(\alpha)\cos(\beta)-\sin(\alpha)\sin(\beta)\tan(\alpha+\beta) = \frac{\tan(\alpha)+\tan(\beta)}{1-\tan(\alpha)\tan(\beta)}.

Recall that given a right triangle, the sin(theta) is defined by opposite side/hypotenuse. Since we know that the angle is in quadrant 2, we know that x should be a negative number. We will use pythagoras theorem to find out the value of x. We have that

x^2+4^2 = 7 ^2

which implies that x=-\sqrt[]{49-16} = -\sqrt[]{33}. Recall that cos(theta) is defined by adjacent side/hypotenuse. So, we know that the hypotenuse is 7, then

\cos(\theta) = \frac{-\sqrt[]{33}}{7}

b)Recall that \sin(\frac{\pi}{6}) =\frac{1}{2} , \cos(\frac{\pi}{6}) = \frac{\sqrt[]{3}}{2}, then using the identity from above, we have that

\sin(\theta + \frac{\pi}{6}) = \sin(\theta)\cos(\frac{\pi}{6})+\cos(\alpha)\sin(\frac{\pi}{6}) = \frac{4}{7}\frac{1}{2}-\frac{\sqrt[]{33}}{7}\frac{\sqrt[]{3}}{2} = \frac{-3\sqrt[]{11}+4}{14}

c) Recall that \sin(\pi)=0, \cos(\pi)=-1. Then,

\cos(\theta-\pi)=\cos(\theta)\cos(\pi)+\sin(\theta)\sin(\pi) = \frac{-\sqrt[]{33}}{7}\cdot(-1) + 0 = \frac{\sqrt[]{33}}{7}

d) Recall that \tan(\frac{\pi}{4}) = 1 and \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}=\frac{-4}{\sqrt[]{33}}. Then

\tan(\theta+\frac{\pi}{4}) = \frac{\tan(\theta)+\tan(\frac{\pi}{4})}{1-\tan(\theta)\tan(\frac{\pi}{4})} = \frac{\frac{-4}{\sqrt[]{33}}+1}{1+\frac{4}{\sqrt[]{33}}}

5 0
3 years ago
30 POINTS!!! <-----
MAVERICK [17]
Y would be your answer
7 0
4 years ago
Convert the height 1,91m to feet​
Andrews [41]
Hi!
The answer is 6.2664 feet!
Hope this helps:))
4 0
4 years ago
Use Pascal’s Triangle to determine the fifth term of the expansion of (x − 5)6.
Alenkasestr [34]

Answer:

I need to see the choices for it

Step-by-step explanation:

6 0
3 years ago
Find the area of the parallelogram that has a base of 2 1/2 ft and a height of 1 1/4ft
Marina CMI [18]

Answer:

The area of the parallelogram is 3\frac{1}{8}ft^{2}

Step-by-step explanation:

Remember that a mixed fractions are composed for a whole number, a numerator and a denominator. For example in the mixed fraction 2\frac{1}{3}: 2 is the whole number, 1 is the numerator and 3 is the denominator.

If you want to convert to a improper fraction you need to multiply the whole number by the denominator and add to the numerator. The result will be the numerator of the improper fraction. The denominator remains the same.

2\frac{1}{3}=\frac{(2*3)+1}{3} =\frac{7}{3}

1. Convert the mixed fractions in the improper fraction type, as follows:

Base= 2\frac{1}{2}=\frac{5}{2} \\ \\Height= 1\frac{1}{4}=\frac{5}{4}

2. Replace the data in the equation of a parallelogram

Area= Base*Height

Area= Base*Height\\Area=\frac{5}{2}ft *\frac{5}{4}ft\\Solve...\\Area=\frac{25}{8}ft^{2}

3. Convert the improper fraction in a mixed fraction

Area=\frac{25}{8}ft^{2}=3\frac{1}{8}ft^{2}

The area of the parallelogram is 3\frac{1}{8}ft^{2}

5 0
3 years ago
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