Answer:
- sin = -√3/2
- cos = -1/2
- tan = √3
- sec = -2
- csc = (-2/3)√3
- cot = (√3)/3
Step-by-step explanation:
See the attached picture for a drawing of the angle and its terminal point coordinates. Those are (cos(4π/3), sin(4π/3)), so we have the following trig function values:
sin(4π/3) = -√3/2
cos(4π/3) = -1/2
tan(4π/3) = sin/cos = √3
sec(4π/3) = 1/cos = -2
csc(4π/3) = 1/sin = -(2√3)/3
cot(4π/3) = 1/tan = (√3)/3
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<em>Additional comment</em>
It helps to know that 1/√a = (√a)/a. This lets you write the ratios with a rational denominator in each case.
C, I’m pretty sure
Why do I have to write 20 words for this? This is why I’m rambling.
The pH of the weak acid is 3.21
Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :
![[H^{+}]=\sqrt{Ka . Ma}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D%5Csqrt%7BKa%20.%20Ma%7D)
where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.
Since we know the concentration of H+, the pH can be calculated by using
pH = -log[H+]
From question above, we know that :
Ma = 0.0250M
Ka = 1.5 x 10¯⁵
By using the equation, we can determine the concentration of [H+]
[H+] = √(Ka . Ma)
[H+] = √(1.5 x 10¯⁵ . 0.0250)
[H+] = 6.12 x 10¯⁴ M
Substituting the value of [H+] to get the pH
pH = -log[H+]
pH = -log(6.12 x 10¯⁴)
pH = 3.21
Hence, the pH of the weak acid c3h7cooh is 3.21
Find more on pH at: brainly.com/question/14466719
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You'd find the vertical asymptotes by seeing where the denominator equals zero; you can do so by factoring the denominator.
In this case, you can factor the denominator into (x+3)(x+2), so if you set each of those equal to zero you can find the equations of the vertical asymptotes (x=-3 and x=-2).
