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3 years ago

Please help please please

Mathematics

1 answer:

diamong [38]3 years ago

8 0

Answer:

Step-by-step explanation:

there is only 4 of her ponies that are over 96 centimeters but it is not 40 percent but 27 percent because she has 14 ponies not 10 ponies

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I need help with this question ASAP!!!

alex41 [277]

I’m not sure sorry also it past due

4 0

3 years ago

Question 4 of 10 A construction worker needs to put a rectangular window in the side of a building. He knows from measuring that

vagabundo [1.1K]

Answer:

❝ D. 13 feet ❞

Step-by-step explanation:

Here,

Window is in the rectangular shape.
Measure of its one diagonal is 13 feet.

According to the properties of rectangle,

→ Diagonals of a rectangle are equal.

So, here the length of other diagonal will be 13 feet too.

7 0

3 years ago

Please help me!!!!!!!!

belka [17]

Answer:

fraction is 75/100

decimal is 0.75

Step-by-step explanation:

because there are 75 of them that are shaded out if 100 so 75/100 and to find out in decimal 75÷100=0.75.

hope this helps u understand:)

4 0

3 years ago

Which rules of exponents will be used to evaluate the expression. Check all that apply

julia-pushkina [17]

Hello!

The answer are:

- Product of powers.

- Power of a power.

- Negative exponents.

Let's solve it!

It's a math rule that we must solve first what's into a brake or parenthesis, so,

First: Product of powers $[(7)^{5}*(7)^{3}]$

According to the exponent's law, we have a product of powers case, so, we need to sum the exponents and keep the base

Exponents: 5 and 3

Base: 7

Applying it we have:

$(7)^{5+3}$

$(7)^{8}$

Then,

We have a power of a power case, which involves multiplying the exponents:

$[(7)^{5}*(7)^{3}]^{-4}$

Exponents: 3 and -4

Then,

$(7)^{8*-4}$

Finally, we can apply the negative exponents, the negative exponent's rules state that negative exponents are the reciprocal of the positive exponents,

So, we will have that:

$(7)^{-32}=\frac{1}{7^{32} }$

Have a nice day!

6 0

3 years ago

Read 2 more answers

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

Paha777 [63]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

We know that,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

Using the trigonometric ratios, we get

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Hence, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

6 0

3 years ago