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dalvyx [7]
3 years ago
15

The weights of steers in a herd are distributed normally. The variance is 10,000 and the mean steer weight is 1400lbs. Find the

probability that the weight of a randomly selected steer is between 1539 and 1580lbs. Round your answer to four decimal places.
Mathematics
1 answer:
saw5 [17]3 years ago
5 0

Answer:

P(1539

And we can find this probability using the normal standard table with this difference:

P(1.39

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(1539,1580)  

Where \mu=1400 and \sigma=\sqrt{10000}= 100

We are interested on this probability

P(1539

And we can solve the problem using the z score formula given by:

z=\frac{x-\mu}{\sigma}

Using this formula we got:

P(1539

And we can find this probability using the normal standard table with this difference:

P(1.39

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