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3 years ago

Please help me!! I’m behind and really need help!

Mathematics

2 answers:

bearhunter [10]3 years ago

5 0

Answer:

the third one is the correct answer

gtnhenbr [62]3 years ago

3 0

Answer:

you selected the right answer already

Step-by-step explanation:

every hour he makes 25 dollars. so 2=50 and 3=75 :)

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A dolphin jumps from the water at a initial velocity of 16 feet per second the equation h=-8t^2 + 16t models the dolphins height

german

Answer:

The answer to the equation -8t^2+16t = -48

Step-by-step explanation:

Add ''-8t^2'' to ''16t'' and the answer you get is ''-48''

6 0

3 years ago

Read 2 more answers

Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra

katen-ka-za [31]

You made a mistake with the probability $p_{j}$ , which should be $p_{i}$ in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer $j$ , is given by:

(1) $\frac{p_{j} }{1-d_{i}p_{i} } , if j \neq i,$ and

(2) $\frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} } , if j = i.$

so we can say:

$A$ is the event that you search drawer $i$ and find nothing,

$B$ is the event that you search drawer $i$ and find the paper,

$C_{k}$ is the event that the paper is in drawer $k, k = 1, ..., n.$

this gives us:

$P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}$

$P(A) = 1 - P(B) = 1 - d_{i} p_{i}$

Solution to Part (1):

if $j \neq i$ , then $P(A \cap C_{j} ) = P(C_{j} )$ ,

this means that

$P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)} = \frac{P(C_{j} )}{P(A)} = \frac{p_{j} }{1-d_{i}p_{i} }$

as needed so part one is solved.

Solution to Part(2):

so we have now that if $j$ = $i$ , we get that:

$P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}$

remember that:

$P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}$

this implies that:

$P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )$

so we just need to combine the above relations to get:

$P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} }$

as needed so part two is solved.

8 0

4 years ago

Which graph does not represent a function that is always increasing over the entire interval -2 < x < 2?

Novay_Z [31]

Answer:

The answer is C

Step-by-step explanation:

I got my answer from quizlet

8 0

3 years ago

The picture is down below please help me

Triss [41]

Check the picture below.

6 0

3 years ago

23. The mean weight of trucks traveling on a particular section of 1-475 is not known. A state highway inspector needs an estima

Free_Kalibri [48]

Answer:

0.3594 = 35.94% probability that a truck will weigh less than 14.3 tons

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean is 15.8 tons, with a standard deviation of the sample of 4.2 tons.

This means that $\mu = 15.8, \sigma = 4.2$

What is probability that a truck will weigh less than 14.3 tons?

This is the pvalue of Z when X = 14.3. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{14.3 - 15.8}{4.2}$

$Z = -0.36$

$Z = -0.36$ has a pvalue of 0.3594

0.3594 = 35.94% probability that a truck will weigh less than 14.3 tons

6 0

3 years ago