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3 years ago

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A florist used the equation Y=KX to determine how many flowers she'd need for 7 bouquets. She determined she'd need 175 flowers.

How many flowers were in each bouquet?

1 answer:

vivado [14]3 years ago

8 0

Answer:

25

Step-by-step explanation:

because 175/7= 25

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If the square root of p2 is an integer greater than 1, which of the following must be true? I. p2 has an odd number of positive

Grace [21]

Answer:

Option | and Option || is True

Step-by-step explanation:

Given:

If the square root of $p^{2}$ is an integer greater than 1,

Lets p = 2, 3, 4, 5, 6, 7..........

Solution:

Now we check all option for $p^{2}$

Option |.

$p^{2}$ has an odd number of positive factors.

Let $p=2$

The positive factor of $2^{2}=4=1,2,4$

Number of factor is 3

Let $p=3$

The positive factor of $3^{2}=9=1,3,9$

Number of factor is 3

So, $p^{2}$ has an odd number of positive factors.

Therefore, 1st option is true.

Option ||.

$p^{2}$ can be expressed as the product of an even number of positive prime factors

Let $p=2$

The positive factor of $2^{2}=4=1,2,4$

$4=2\times 2$

Let $p=3$

The positive factor of $3^{2}=9=1,3,9$

$9=3\times 3$

So, it is expressed as the product of an even number of positive prime factors,

Therefore, 2nd option is true.

Option |||.

p has an even number of positive factors

Let $p=2$

Positive factor of $2=1,2$

Number of factor is 2.

Let $p=4$

Positive factor of $4=1,2,4$

Number of factor is 3 that is odd

So, p has also odd number of positive factor.

Therefore, it is false.

Therefore, Option | and Option || is True.

Option ||| is false.

4 0

3 years ago

emma has 15 cookies and eats 2 cookies per day evan has 45 cookies and eats 8 each day how would you write and solve an equation

erastovalidia [21]

Lets say cookies = x and days = y.

2x times y = 15.

8x times y = 45.

7 0

3 years ago

Read 2 more answers

What's the pattern for 2,4,7,9

Semenov [28]

Answer:

The pattern is this: I create a function p(x) such that

p(1)=1

p(2)=1

p(3)=3

p(4)=4

p(5)=6

p(6)=7

p(7)=9

Therefore, trivially evaluating at x=8 gives:

p(8)= 420+(cos(15))^3 -(arccsc(0.304))^(e^56) + zeta(2)

Ok, I know this isn’t what you were looking for. Be careful, you must specify what type of pattern is needed, because the above satisfies the given constraints.

Step-by-step explanation:

4 0

3 years ago

What is 27/125 in exponential form?

stealth61 [152]

3/5 I think is the answer

8 0

3 years ago

Read 2 more answers

A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3><u>Solution:</u></h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

<em><u>The area of rectangle is given as:</u></em>

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

<em><u>General form of quadratic equation is </u></em>

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0

3 years ago