N^2-4n
Help please thanksss
1 answer:
Answer:
Two solutions are found:
n=0 , n= 4 ....
Step-by-step explanation:
n^2-4n = 0
Take common from the given expression:
n(n-4)=0
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately;
n(n-4)=0
n = 0.
n-4 = 0.
Add 4 at both sides:
n-4+4 = 0+4
n = 4
Therefore two solutions are found:
n=0 , n= 4 ....
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