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3 years ago

I need major help. I have a time limit. Please help

Mathematics

2 answers:

inessss [21]3 years ago

8 0

Answer:

what u need help with

cuz I can help u if u need help

Art [367]3 years ago

5 0

Answer:

$24

Step-by-step explanation:

Ten percent of 20 is 2.

The problem never says if he deposited any more money, so the account will always be at 20 dollars without interest.

If Lonny has his bank account for 2 years, the interest will be doubled.

Now, the interest is 20 percent.

If 10 percent of 20 is 2, then 20 percent will be 4.

Add 4 to 20 and you get 24.

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Determine the product: (46.2 × 10–1) ⋅ (5.7 × 10–6). Write your answer in scientific notation.

lianna [129]

Answer:

Step-by-step explanation:

10-6 X 10-1 = 10-7

5.7*46.2=263.34

263.34=2.6334 x 10^2

10^2 x 10^-7 = 10^-5

=2.6334 x 10-5

7 0

3 years ago

Milo is volunteering at a food pantry. In the first hour, he packs 3 boxes every

garri49 [273]

14 boxes per hour
60/5=12
12*3=36
60/6=10
10*5=50
50-36=14

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3 years ago

At the Sunnyvale Play House, the price for an adult ticket is $12 and the price of a child's ticket is $6. For Saturday night's

Rzqust [24]

Answer:

a + c = 125 & 12a + 6c = 1140

Step-by-step explanation:

adult ticket total + child ticket total = 125 total tickets

($12 x adult ticket total) + ($6 x child ticket total) = $1140

4 0

3 years ago

What is Depreciation and Amortization?

ladessa [460]

“Amortization and depreciation are two methods of calculating the value for business assets over time. ... Amortization is the practice of spreading an intangible asset's cost over that asset's useful life. Depreciation is the expensing of a fixed asset over its useful life.”

3 0

2 years ago

Read 2 more answers

Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

$P(x \ge 60) \approx P(z > 1.34)$

$= 1-P(z \le 1.34)$

$=1-0.9099$

$=0.0901$

3 0

3 years ago