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liberstina [14]
3 years ago
9

at Herman's Bakery 40% of the total cookies made last week where oatmeal cookies. if 20 cookies were oatmeal how many total cook

ies were made last week​
Mathematics
1 answer:
Doss [256]3 years ago
6 0

Answer:

50 cookies were made last week

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<img src="https://tex.z-dn.net/?f=%20-%208y%20%5Cgeqslant%2056" id="TexFormula1" title=" - 8y \geqslant 56" alt=" - 8y \geqslant
SCORPION-xisa [38]

Answer:

y ≤-7

Step-by-step explanation:

-8y ≥56

Divide each side by -8.  Remember to flip the inequality

-8y/-8 ≤56/-8

y ≤-7

8 0
3 years ago
You are paid $8.90 an hour for a 35-hour work week. You would like to work 5 hours a week overtime to earn extra money. How much
jeyben [28]

Answer:

$66.75 is what you'll make from over time.(this does not include the pay from the 35 hours this is only the over time)

Step-by-step explanation:

If you were to work (WITH OUT OVERTIME) you would have $311.50

If you were to work (WITH OVERTIME INCLUDED) you would get $378.25

5 0
3 years ago
Write a fraction, a decimal, and a percent that sum to 1 or 100%.
NemiM [27]

Answer:

Fraction: 1/1, 2/2, 3/3, 4/4, 5/5, 6/6, 7/7, 8/8, 9/9, 10/10 etc.

Decimal: 1.00

Percent: 100%

3 0
3 years ago
Read 2 more answers
I need help show your work
Vlad1618 [11]
If x = 2 than, 6(4x2)=48
-3(8x)= -24
It would equal 24
6 0
3 years ago
Read 2 more answers
Find the least common multiple of these two expressions. 15x^7y^3u^8 and 6y^4u^5
snow_tiger [21]

Answer:

30x^7y^4u^8

Step-by-step explanation:

We have been given two expressions 15x^7y^3u^8 and

6y^4u^5

Now we need to find out least common multiple of these two expressions.

First we need to find out what is common factor of both expressions. 15x^7y^3u^8 and

6y^4u^5

Least common multiple means find the expression which can be divided by both expressions.

15 and 6 both goes into 30

so 30 is part of LCM (least common multiple )

Now pickup the highest exponent of each variable.

So we get x^7y^4u^8

Hence required least common multiple is 30x^7y^4u^8

8 0
3 years ago
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