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2 years ago

Pls help I need it quickly thanks

Mathematics

1 answer:

koban [17]2 years ago

5 0

Answer:

56n thats what ben said

Step-by-step explanation:

hohoho corent answer

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What is the fifth term of (x-2y)^7

Vladimir79 [104]

Answer:

560x^3y^4.

Step-by-step explanation:

The (r+1)th term of (a + b)^r = nCr a^(n-r) b^r

We want the fifth term so r = 5 - 1 = 4:

(4 + 1)th term = 7C4 x^(7-4) (-2y)^4

= 35x^3 16y^4

= 560x^3y^4.

3 0

3 years ago

Variable p is 2 more than variable d. Variable p is also 1 less than variable d. Which pair of equations best models the relatio

goldenfox [79]

If you would like to find a pair of equations that best models the relationship between p and d, you can do this using the following steps:

p is 2 more than d ... p = d + 2
p is 1 less than d ... p = d - 1

The correct result would be p = d + 2 and <span>p = d - 1.</span>

4 0

3 years ago

Read 2 more answers

How do I solve this?

Svetradugi [14.3K]

Answer: x = 15; y = 32; z = 2.5

see in the picture, u can see that this parallelogram has a right angle and two adjacent equal edges.

=> this parallelogram is a square

=> the diagonal lines of the parallelogram are perpendicular to each other

=> m∠1 = 90°

⇔ 3y - 6 = 90

⇔ 3y = 96

⇔ y = 32

because this is a square

=> 3x = 18z = 45°

=> x = 15

z = 2.5

Step-by-step explanation:

7 0

3 years ago

Pls help ill give brainleist

Vinvika [58]

3 no. Answer is 33 in my gess

4 0

3 years ago

Chicken Delight claims that 90% of its orders are delivered within 10 minutes of the time the order is placed. A sample of 90 or

kkurt [141]

<h2>Answer with explanation:</h2><h2></h2>

Let p be the population proportion of orders are delivered within 10 minutes of the time the order is placed.

Then according to the claim we have ,

$H_0:p=0.90\\\\ H_a:p\neq0.90$

Since the alternative hypothesis is two-tailed so the hypothesis test is a two-tailed test.

For sample ,

n = 90

Proportion of orders are delivered within 10 minutes of the time the order is placed= $\hat{p}=\dfrac{80}{90}\approx0.89$

Test statistics for population proportion :-

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\=\dfrac{0.89-0.90}{\sqrt{\dfrac{0.90(0.10)}{90}}}\approx-0.32$

The p-value : $2(z>-0.32)=0.7489683\approx0.75$ [By using standard normal distribution table]

Since the p-value is greater that the significance level (0.01), so we do not reject the null hypothesis.

Hence, we conclude that we have enough evidence to support the claim that 90% of its orders are delivered within 10 minutes of the time the order is placed.

4 0

3 years ago