The details of the packages are not posted, however I can tell you how to find the answer.
First determine how many pencils are in each pack.
Then divide the price of the pack by the number of pencils to find out which pack has the least cost per pencil. To put this in equation form:
Whichever pack has the least cost per pencil is the one that is the best priced.
<u>Explanation </u><u>:</u>
<u>Given that:</u>
- In a box 25 cards are there and 1 to 25 numbers are written on them.
- • One card is drawn randomly.
<u>To Find:</u>
- • What is the probability that it is multiple of 5.
<u>We know that:</u>
P(E)= F/T
<u>Where,</u>
P(E)= Probability of an event
• F= Favourable outcomes . T = Total outcomes
<u>We have:</u>
F = Number of cards which are multiple of 5
Cards having the number 5, 10, 15, 20, 25 are the multiples of 5.
So, F = 5
T = Total number of cards
• T = 25
P(F) The probabilityP(E) = The probability that it is multiple of 5
Finding the probability that it is multiple of 5:
<u>Hence,</u>
The probability that it is multiple of 5 is ⅕
Answer:
1771 possible ways
Step-by-step explanation:
In this case, we need to know first how many candidates are in total:
10 + 3 + 10 = 23 candidates in total.
Now, we need to choose 3 of them to receive an award. In this case, we have several scenarios, but as it's an award we can also assume that the order in which the candidates are chosen do not matter, so, the formula to use is the following:
C = m! / n! (m - n)!
Where m is the total candidates and n, is the number of candidates to be chosen. Replacing this data we have:
C = 23! / 3! (23 - 3)!
C = 2.59x10^22 / 6(2.43x10^18)
C = 1771
So we have 1771 ways of choose the candidates.
