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3 years ago

Factor the linear expression 15x – 10 using the greatest common factor of the terms.

Mathematics

2 answers:

kaheart [24]3 years ago

6 0

Answer:

Step-by-step explanation:

Citrus2011 [14]3 years ago

4 0

Answer:

The answer is D.

Step-by-step explanation:

hope that helps

Solutions:

A. 5(3x + 2)

= 15x+10

B. 5(3x – 10)

= 15x-50

C. 15(x – 2)

= 15x-30

D. 5(3x – 2)

=15x-10

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Assume the readings on thermometers are normally distributed with a mean of 0degreesc and a standard deviation of 1.00degreesc.

Tanzania [10]

Let Z be the reading on thermometer. Z follows Standard Normal distribution with mean μ =0 and standard deviation σ=1

The probability that randomly selected thermometer reads greater than 2.07 is

P(z > 2.07) = 1 -P(z < 2.07)

Using z score table to find probability below z=2.07

P(Z < 2.07) = 0.9808

P(z > 2.07) = 1- 0.9808

P(z > 2.07) = 0.0192

The probability that a randomly selected thermometer reads greater than 2.07 is 0.0192

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3 years ago

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Anna35 [415]

X=121
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3 years ago

No links or wrong answers please!! 55 points

juin [17]

The areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)

<h3>How to determine the total areas?</h3>

<u>The figure 1</u>

In this figure, we have

Length = x + 1

Width = 4

The area is calculated as:

Area = Length * Width

So, we have

Area = 4(x + 1)

<u>The figure 2</u>

In this figure, we have

Length = d + 4

Width = 7

The area is calculated as:

Area = Length * Width

So, we have

Area = 7(d + 4)

<u>The figure 3</u>

In this figure, we have

Length = y + 3

Width = y

The area is calculated as:

Area = Length * Width

So, we have

Area = y(y + 3)

Hence, the areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)

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2 years ago

Given ∆ABC with vertices A(−4, −3), B(0, 0), C(2, −3) and ∆DEF with vertices D(3, 1), E(6, -3), F(3, −5), use the definition of

dimaraw [331]

By SSS congruency criteria ΔABC ≅ ΔDEF

<h3>What is congruency?</h3>

Two figures or objects are congruent if they have the same shape and size, or if one has the same shape and size as the mirror image of the other.

The given vertices of the triangles are;

ΔABC: A(−4, −3), B(0, 0), C(2, −3)

ΔDEF: D(3, 1), E(6, -3), F(3, −5)

The lengths of the sides of ΔABC are

AB = √((0+4)² + (0+3)²) = √25 = 5

BC = √((2-0)² + (-3 - 0)²) = √13

AC = √((2+4)² + (-3 +3)²) = √36 = 6

The lengths of the sides of ΔDEF are;

DE = √25=5

EF = √13

DF = √36 = 6

As,

AB= DE, BC = EF , AC= DF

So, By SSS congruency criteria ΔABC ≅ ΔDEF

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2 years ago

The average of five numbers is 18. let the first number be increased by 1, the second number by 2, the third number by 3, the fo

grandymaker [24]

It sounds like initially we have a total of 18*5 = 90. Then we are adding 5 + 4 +3 +2 +1 to this.
so that gives us 105.

105/5 = 21

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3 years ago