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qaws [65]
2 years ago
7

1

Mathematics
1 answer:
galina1969 [7]2 years ago
7 0

Answer:

X .

-1 | 2

-11-1

-11-4

0 3

2 1-1

-13

0

0

-4-1

--3 0

-1 2

-1 1

0 3

2-5

0 0

2

2

3

3

A. III

B.IV

C.

D

1\

Step-by-step explanation:

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What are the X and Y intercepts of y= -2(x-4)2 +3
kari74 [83]

Answer: x-intercepts are ( 2.775,0) and (5.225,0)

And y-intercept is (0,-29)

Step-by-step explanation:

Here the given equation is,

y = -2(x-4)^2+3

For x-intercept, y = 0,

Put y = 0 in the above equation of parabola,

We get, -2(x-4)^2 + 3 = 0

-2(x^2+16+8x) + 3 = 0

-2x^2-32-16x + 3 = 0

-2x^2-16x -29 = 0

By solving this equation,

We get, x = 2.775 or x = 5.225

Therefore, x-intercept of the given parabola are (2.775, 0) and (5.225,0)

Now, for y-intercept, x = 0

By putting x = 0 in the given equation of parabola,

We get, y = -29

Thus, y-intercept of the given parabola = (0,-29)



4 0
3 years ago
Which statement is NOT true?
riadik2000 [5.3K]
And integer is a whole number, negative or positive,  with no decimals or fractions.
A is true.
B is true.
A rational number is a number that doesn't have an infinite number of decimal.
C is true.
D is false.
<u>The answer is D</u>

8 0
3 years ago
Sqrt of 4a-4 + sqrt of a-1
Monica [59]
\large\begin{array}{l} \textsf{Simplify the expression (I'm goint to call it E)}\\\\ \mathsf{E=\sqrt{4a-4}+\sqrt{a-1}} \end{array}


\large\begin{array}{l} \textsf{So E is a sum of two square roots. Notice that you can factor}\\\textsf{the 4 out on the first one:}\\\\ \mathsf{E=\sqrt{4\cdot a-4\cdot 1}+\sqrt{a-1}}\\\\ \mathsf{E=\sqrt{4\cdot (a-1)}+\sqrt{a-1}}\\\\ \mathsf{E=\sqrt{2^2\cdot (a-1)}+\sqrt{a-1}}\\\\ \mathsf{E=\sqrt{2^2}\cdot \sqrt{a-1}+\sqrt{a-1}}\\\\ \mathsf{E=2\cdot \sqrt{a-1}+\sqrt{a-1}} \end{array}

\large\begin{array}{l} \mathsf{E=2\cdot \sqrt{a-1}+1\cdot \sqrt{a-1}}\\\\ \mathsf{E=(2+1)\cdot \sqrt{a-1}}\\\\ \boxed{\begin{array}{l}\mathsf{E=3\cdot \sqrt{a-1}} \end{array}} \end{array}


If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2179170


\large\textsf{I hope this helps. :-)}


Tags: <em>square root sqrt simplify expression radical irrational algebra</em>

5 0
3 years ago
Mina drew 15hearts,6stars and 16 circles.What is the ratio of stars to hearts to circles?
GenaCL600 [577]

answer

6:15:16

step-by-step explanation

the ratio of stars to hearts to circles is stars:hearts:circles

plug in 6 for stars, 15 for hearts, and 16 for circles

6:15:16

since these do not have a common factor, this is your final answer

7 0
3 years ago
Read 2 more answers
Evaluate the series
dalvyx [7]

Answer:

the value of the series;

\sum_{k=1}^{6}(25-k^2) = 59

C) 59

Step-by-step explanation:

Recall that;

\sum_{1}^{n}a_n = a_1+a_2+...+a_n\\

Therefore, we can evaluate the series;

\sum_{k=1}^{6}(25-k^2)

by summing the values of the series within that interval.

the values of the series are evaluated by substituting the corresponding values of k into the equation.

\sum_{k=1}^{6}(25-k^2) =(25-1^2)+(25-2^2)+(25-3^2)+(25-4^2)+(25-5^2)+(25-6^2)\\\sum_{k=1}^{6}(25-k^2) =(25-1)+(25-4)+(25-9)+(25-16)+(25-25)+(25-36)\\\sum_{k=1}^{6}(25-k^2) =24+21+16+9+0+(-11)\\\sum_{k=1}^{6}(25-k^2) = 59\\

So, the value of the series;

\sum_{k=1}^{6}(25-k^2) = 59

6 0
3 years ago
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