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2 years ago

7

1

1 answer:

galina1969 [7]2 years ago

7 0

Answer:

X .

-1 | 2

-11-1

-11-4

0 3

2 1-1

-13

0

0

-4-1

--3 0

-1 2

-1 1

0 3

2-5

0 0

2

2

3

3

A. III

B.IV

C.

D

1\

Step-by-step explanation:

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A school has over 500 students, 30 English teachers, and 20 math teachers. What is the ratio between the number of math teachers

aliina [53]

The ratio is 1:25 (simplified) or 20:500

6 0

3 years ago

Intersection point of Y=logx and y=1/2log(x+1)

GalinKa [24]

Answer:

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

The Problem:

What is the intersection point of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ ?

Step-by-step explanation:

To find the intersection of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ , we will need to find when they have a common point; when their $x$ and $y$ are the same.

Let's start with setting the $y$ 's equal to find those $x$ 's for which the $y$ 's are the same.

$\log(x)=\frac{1}{2}\log(x+1)$

By power rule:

$\log(x)=\log((x+1)^\frac{1}{2})$

Since $\log(u)=\log(v)$ implies $u=v$ :

$x=(x+1)^\frac{1}{2}$

Squaring both sides to get rid of the fraction exponent:

$x^2=x+1$

This is a quadratic equation.

Subtract $(x+1)$ on both sides:

$x^2-(x+1)=0$

$x^2-x-1=0$

Comparing this to $ax^2+bx+c=0$ we see the following:

$a=1$

$b=-1$

$c=-1$

Let's plug them into the quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$x=\frac{1 \pm \sqrt{1+4}}{2}$

$x=\frac{1 \pm \sqrt{5}}{2}$

So we have the solutions to the quadratic equation are:

$x=\frac{1+\sqrt{5}}{2}$ or $x=\frac{1-\sqrt{5}}{2}$ .

The second solution definitely gives at least one of the logarithm equation problems.

Example: $\log(x)$ has problems when $x \le 0$ and so the second solution is a problem.

So the $x$ where the equations intersect is at $x=\frac{1+\sqrt{5}}{2}$ .

Let's find the $y$ -coordinate.

You may use either equation.

I choose $y=\log(x)$ .

$y=\log(\frac{1+\sqrt{5}}{2})$

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

6 0

2 years ago

2765÷9 in long division

Kruka [31]

$9\sqrt{2765}$ and the total is 307.222222

6 0

2 years ago

I need helpppppppp I don’t like remainders :/

den301095 [7]

Answer:

The correct answer is 67 9/11

4 0

2 years ago

Read 2 more answers

A square has sides measuring 3 feet. If the sides of a square are doubled, will the area also double? Explain

Kryger [21]

Hello!

Let's find the area and see!

A = s^2

A = 3^2

A = 6 ft^2

Now, if you double 3, you get 6. 3 × 2 = 6 Find the area:

A = 6^6

A = 36 ft^2

ANSWER:

No, the area will not be doubled. The area was 9 ft^2 when the sides were 3 feet long. If you double 9, you get 18, since 9 × 2 = 18.

36 is not the double of 9, so no, the area is not double.

8 0

3 years ago