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kvv77 [185]
3 years ago
15

Please help my friend

Mathematics
1 answer:
storchak [24]3 years ago
4 0

64 feet because you add both the distances together.

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How do you graph y= -7x-1?<br> Show the coordinates and graph.
aliya0001 [1]

Answer:

You start at -1 because its your y-intercept and from there you go 7 down and 1 to the right

Step-by-step explanation:

6 0
2 years ago
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What is the property of this equation? if 2x=8 then x=4
Eva8 [605]
Answer is 2 x 4=8 this is a scientific property
7 0
3 years ago
A food company distributes its tomato soup in two cans of different sizes. For the larger can, the diameter has been increased b
Murrr4er [49]

Answer:

Step-by-step explanation:

buenas tardes .....

solucion

Volumen de un cilindro: es igual al área de la tapa por la altura del mismo

A = πD² * h / 4

Lata grande y lata pequeña

Para la lata grande, el diámetro y la altura han aumentado un 20%.

Lata pequeña:

d = 4 cm

h = 3 cm

A 1 = π * (4) ² * 3/4

A1 = 37,70 cm²

Lata grande:

d = 4 * 1,2 = 4,8 cm

h = 3 * 1,2 = 3,6 cm

A2 = π (4,8) ²3,6 / 4

A2 = 65,14 cm²

Si 37,7 representa el 100%

  65,14 representación x

x = 170%

El incremento del volumen es de un 70%

6 0
3 years ago
Select the values that make the inequality y≥2y≥2 true.
ExtremeBDS [4]

9514 1404 393

Answer:

  {2, 2.001, 2.01, 2.1, 3, 5, 7, 10}

Step-by-step explanation:

The symbol ≥ means "greater than or equal to", so any values 2 or greater will make the inequality true. From your list, those are ...

  2 2.001 2.01 2.1 3 5 7 10

3 0
3 years ago
85.87 J or heat energy is added to a 34.8 g mass of substance the temperature rises from 21.76°C
Andru [333]

Answer:

The required specific heat is 196.94 joule per kg per °C  

Step-by-step explanation:

Given as :

The heat generated = Q = 85.87 J

Mass of substance  (m)= 34.8 gram = 0.0348 kg

Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C

Let the specific heat = S

Now we know that

Heat = Mass × specific heat × change in temperature

Or, Q = msΔt

Or, 85.87 = (0.0348 kg ) × S × 12.53°C

Or , 85.87 = 0.4360 × S

Or, S = \frac{85.87}{0.4360}

∴ S = 196.94 joule per kg per °C

Hence the required specific heat is 196.94 joule per kg per °C   Answer

7 0
3 years ago
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