If you mean greatest common factor then that means
factor each and group the ones that are same
81=3 times 3 times 3 times 3
108=2 times 2 times 3 times 3 times 3
117=3 times 3 times 13
so we look for the group common to all (I bolded it)
81=3 times 3 times 3 times 3
108=2 times 2 times 3 times 3 times 3
117=3 times 3 times 13
the answeis 3 times 3=9
greates common denomenator of these nubers is 9
Approaching algebraicly(Take 2 as x)
(-x)^3-x^3
Simplify
Result is -2x^3
Put back 2
-2(2)^3 = -2(8)
= -16
Answer:
Step-by-step explanation:
The arithmetic series is
From the given series the general term of the series is
When , we substitute into the general formula to get:
When k=2, we get:
When k=3, we substitute to get:
When k=4, we substitute to get:
When k=5, we get:
Answer:
Step-by-step explanation: