Question

Daniel Potter bought a new car for $20,000.02 years later he wanted to sell it he was after $14,650 for it if he sold it for that amount what was his deprecation Marie

Answer 1

well, my name is not Marie, but I hope is ok if I post on it.

$\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\to &14650\\ P=\textit{initial amount}\to &20000\\ r=rate\to r\%\to \frac{r}{100}\\ t=\textit{elapsed time}\to &2\\ \end{cases}$

$\bf 14650=20000(1-r)^2\implies \cfrac{14650}{20000}=(1-r)^2\implies \cfrac{293}{400}=(1-r)^2 \\\\\\ \sqrt{\cfrac{293}{400}}=1-r\implies r=1-\sqrt{\cfrac{293}{400}}\implies r=1-\sqrt{0.7325} \\\\\\ r\approx 0.14413786\implies r\%\approx 0.14413786\cdot 100\implies r\approx\stackrel{\%}{14.41}$