The answer would be Theodore Schwann, Matthias Jakob Schleiden and Rudolf Virchow(he contributed but is not credited)
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Answer:
0.48 mols
Explanation:
to convert moles to mass u need to divide mass by the molar mass of NaCl which is 58.44g/mols.
28g ÷ 58.44g/mol = 0.48 mols
Answer:
67162.5 cubic decimetre (dm3) of O2
Explanation:
Step 1:
Write a balance Chemical equation for the following Reaction
KClO3 ---> KCl + 3/2O2
Step 2:
Calculating moles of KClO3:
Molar mass of KClO3 = 122.55 gm
Given Mass = 245 Kg
Moles of KClO3 = 245 / 122.55
Moles of KClO3 = 1.99 Kmol
Step 3:
According to balance Chemical Equation
1 Mole of KClO3 gives 3/2 moles of O2
1.99 KMole(or 1990 moles) gives "x" moles of O2
By balancing for x, we get
x = (3/2)*1990 moles of O2
x = 2985 moles of O2
Step 4:
Calculating Volume of O2 at STP
V = 2985*22.5 dm3
<u><em>V= 67162.5 dm3</em></u>
