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3 years ago

2. How do we identify bias and avoid thinking errors when evaluating online information?

Chemistry

1 answer:

skad [1K]3 years ago

6 0

Answer:

We can identify bias and avoid thinking errors when evaluating online information when there is a certain degree of partiality in the way the information is given. The writer takes one side and doesn’t consider benefits of the other side/view.

We can identify bias and avoid thinking errors when evaluating online information by making our personal findings and research from other sources and then comparing the two.

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6.0 moles of Na and 4.0 moles of Cl2 are mixed, how manu moles of NaCl in moles cane be made from this mixture

Sladkaya [172]

Answer:

Moles of NaCl formed is 6.0 moles

Explanation:

We are given the equation;

2 Na(s) + Cl₂(g) → 2 NaCl(s)

Moles of Na is 6.0 moles
Moles of Cl₂ is 4.0 moles

From the reaction;

2 moles of sodium reacts with 1 mole of chlorine gas to form 2 moles of NaCl

In this case;

6 moles of Na would require 3 moles of Cl₂, this means that chlorine gas is in excess.

Thus, the rate limiting reagent is sodium.

But, 2 moles of sodium reacts to form 2 moles of NaCl

Therefore;

Moles of NaCl = Moles of Na

= 6.0 moles

Thus, moles of sodium chloride produced is 6.0 moles

3 0

3 years ago

Am I doing this right? What is [OH-] of a solution with a pH of 4.0? Answer in M

jok3333 [9.3K]

Am I doing this right?

What is [OH-] of a solution
with a pH of 4.0?

Answer in M
Ya

4 0

3 years ago

A new technology company is marketing drones for residential use. The bar graph shows the relation between number of sales and t

zhuklara [117]

Answer:

1- The graph provides a comparison of the different marketing strategies

2- The graph helps in selecting the best marketing strategy to improve sales

Explanation:

Hope this help

plz mark brainliest

Have a nice day!!!

4 0

4 years ago

A weather balloon is filled with helium that occupies a volume of 500 L at 0.995 atm and 32.0 ℃. After it is released, it rises

Yuki888 [10]

Answer : The volume of the balloon at the new location is, 591.3 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.995 atm

$P_2$ = final pressure of gas = 0.720 atm

$V_1$ = initial volume of gas = 500 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $32.0^oC=273+32=305K$

$T_2$ = final temperature of gas = $-12^oC=273+(-12)=261K$

Now put all the given values in the above equation, we get:

$\frac{0.995atm\times 500L}{305K}=\frac{0.720atm\times V_2}{261K}$

$V_2=591.3L$

Therefore, the volume of the balloon at the new location is, 591.3 L

3 0

4 years ago

A sample of propane (C3H8) has a mass of 0. 47 g. The sample is burned in a bomb calorimeter that has a mass of 1. 350 kg and a

Nady [450]

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

The specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The specific heat has been expressed as:

$q=mc\Delta T$

<h3 /><h3>Computation for the heat absorbed</h3>

The iron and calorimeter are in side the closed system. Thus, the energy released by the sample, has been equivalent to the energy absorbed by the calorimeter.

$q_{released}=q_{absorbed}\\
q_{released}=m_{calorimeter}\;c_{calorimeter}\;\Delta T$

The given mass of calorimeter has been, $m_{calorimeter}=1350\;\rm g$

The specific heat of the calorimeter has been, $c_{calorimeter}=5.82\;\rm J/g^\circ C$

The change in temperature of the calorimeter has been, $\Delta T=2.87^\circ \rm C$

Substituting the values for heat released:

$q_{released}= 1350\;\text g\;\times\;5.82\;\text J/\text g^\circ \text C\;\times\;2.87^\circ \text C\\
q_{released}=22,549.5\;\text J\\
q_{released}}=22.54\;\rm kJ$

The amount of heat released by the sample has been 22.54 kJ. Thus, option C is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

6 0

3 years ago