(3/2)^2÷(1-3/2+√(1/8+7/16))×(1+2/3)^3 ayudaaaaaaaa

8y-2d=0 5y+4d=26 1/4

Anit [1.1K]

Answer:

y = 1

d = 4

Step-by-step explanation:

8y - 2d = 0 ---------------(I)

5y + 4d = 26 1/4

5y + 4d = 105/4 ------------------(II)

(I)*2 16y - 4d = 0

(II) 5y + 4d = 105/4 {add (I) &(II)}

21y = 105/4

$y = \frac{105}{5*21}\\\\y=\frac{105}{105}\\\\y = 1$

Substitute y =1 in equation (I)

8*1 - 2d = 0

8 - 2d = 0

-2d = -8

d = -8/-2

d = 4

7 0

3 years ago

Read 2 more answers

AE and DF are parallel. If √ABG = 11x and m_HCF = 10x + 9, what is m√ABG? 102° 99° 81° 9°

katrin [286]

Answer:

81

Step-by-step explanation:

6 0

3 years ago

The dot plots below show the number of points scored by Sam and Daniel in 15 basketball games.

Bas_tet [7]

Answer:

B.

Step-by-step explanation:

Sam median = 12 which has 3 points scored.

Daniel median = 16 which has 3 points scored.

Both scored the same amount of data which is 3 points.

Both the ranges are 16. so it cant be A or C.

3 0

3 years ago

If anyone Answer this question with POLITICALLY CORRECT answer I'll give you 25+ Points

Tresset [83]

Answer:

$\sqrt[4]{x^5}$

Step-by-step explanation:

A fraction exponent converts into a radical. The denominator is the index of the radical (farthest left number) and the numerator is the exponent of the base inside (the farthest right number). The base of the fraction exponent is the base number in green. To write this expression, simply the exponents into one exponent and one base.

$x^{\frac{3}{4}}x^{\frac{1}{2} } =x^{\frac{3}{4}}x^{\frac{2}{4} } =x^{\frac{3+2}{4}} =x^{\frac{5}{4}}$

Now convert to the radical.

$x^{\frac{5}{4}} = \sqrt[4]{x^5}$

8 0

3 years ago

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

The final curse load of the local gym instructor is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

The final course load is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

7 0

3 years ago