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2 years ago

10

Draw a line to match each real world problem with the expression that can be used to solve it.

2 answers:

S_A_V [24]2 years ago

4 0

Answer:

Lily has 32 ounces of orange Juice. if this is 10% more than sav, how much orange juice does sav have?

Answer = 0.9x =32 and 0.1x=32

Danie is purchasing a new video game controller. After a discount of $32 the cost of the controller is $32. what was the original cost of the controller?

Answer = 1.1x=32

kirill115 [55]2 years ago

3 0

C i hope this helps you

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What are the coordinates of the vertices of the triangle under the translation (x, y) —> (x + 2, y + 3)?

tamaranim1 [39]

For each vertex just take the x and y coordinate and apply the translation. so for the point (-3,-2) make them (-3+2, -2+3)=(-1,1) and do the same for the other two points (0,2) and (-7,3)

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3 years ago

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two fractions with different denominators have a sum of 7/12 what are two possible addends that results in this sum

yawa3891 [41]

1/3+1/4=7/12 because changing the denominators to make them common gives you 4/12+3/12=7/12

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3 years ago

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Evaluate the expression when y=-4.<br> y²-7y+2

harkovskaia [24]

Answer:

Here is your answer

Hope it helps

6 0

3 years ago

Complete the expressions.

solong [7]

Complete question :

Complete the expressions Write each answer as a number, a variable, or the product of a number and a variable 7(9r + 2) = 7 . 9r + 7 . ___ = ___ +

Answer:

2 ; 63r ; 14

Step-by-step explanation:

Given :

7(9r + 2)

Opening the bracket :

7*9r + 7*2 - - - - (1)

Taking the product

63r + 14 - - - - (2)

Now filling the blanks :

First blank corresponds to 2 (from (1))

Second blank corresponds to 63r (from (2))

Third blank should be 14

8 0

3 years ago

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

3 years ago