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Setler [38]
4 years ago
12

Write equation for the line in slope intercept form (6,4) and (3,8)

Mathematics
1 answer:
nikdorinn [45]4 years ago
5 0

Answer: y = - 4x/3 + 12

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = y intercept

m represents the slope of the line.

m = (y2 - y1)/(x2 - x1)

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The line passes through (6, 4) and (3, 8),

y2 = 8

y1 = 4

x2 = 3

x1 = 6

Slope,m = (8 - 4)/(3 - 6) = 4/- 3 = - 4/3

To determine the y intercept, we would substitute x = 3, y = 8 and m= - 4/3 into y = mx + c. It becomes

8 = - 4/3 × 3 + c

8 = - 4 + c

c = 8 + 4

c = 12

The equation becomes

y = - 4x/3 + 12

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To solve this, I would just find what two adult tickets and one child ticket wold be worth.

To find that, just do:

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3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

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(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

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Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

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